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2 years ago

Is the equation a linear function or nonlinear function?

Mathematics

2 answers:

makvit [3.9K]2 years ago

6 0

Answer:

but i think its nonlinear function

Step-by-step explanation:

retype it

iren2701 [21]2 years ago

3 0

Answer:

The above answer is right, it looks like a non-linear equation. I just barely can make out the form of it.

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Divide.

nika2105 [10]

-0.8 that is the answer hope it helps

3 0

3 years ago

Please find the question

melisa1 [442]

Answer:

By distance formula ,

AB² = (5+1)² + (3-6)²

AB² = 36 + 9

AB = 6.71 units

6 0

3 years ago

Assume adults have IQ scores that are normally distributed with a mean of 102 and standard deviation of 16. Find the probability

Andre45 [30]

Answer:

57.49% probability that a randomly selected individual has an IQ between 81 and 109

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 102, \sigma = 16$

Find the probability that a randomly selected individual has an IQ between 81 and 109

This is the pvalue of Z when X = 109 subtracted by the pvalue of Z when X = 81. So

X = 109

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{109 - 102}{16}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

X = 81

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{81 - 102}{16}$

$Z = -1.31$

$Z = -1.31$ has a pvalue of 0.0951

0.67 - 0.0951 = 0.5749

57.49% probability that a randomly selected individual has an IQ between 81 and 109

8 0

3 years ago

A polygraph (lie detector) is an instrument used to determine if an individual is telling the truth. These tests are considered

Leya [2.2K]

Answer:

A) P(Type I error) = 0.045

B) P(Type II) error = 0.1

Step-by-step explanation:

We are told that the reliability of the test is 90% reliable.

Also, we are told that the probability that the test erroneously detects a lie even when the individual is actually telling the truth is 0.045.

Thus;

A) To calculate the probability of type I error:

From statistics, in this question we can say that the probability of a type I error is the probability that the test will erroneously detect a lie even though the individual is actually telling the truth. Thus;

Probability of (type I error) = P(rejecting true null) = 0.045

B) For probability of type II error, it is defined as the error where we accept a null hypothesis that is false. We can say that it produces a false negative and the formula is;

P(Type II) error = 1 - reliability

Reliability in the question is 0.90

Thus;

P(Type II) error = 1 - 0.9

P(Type II) error = 0.1

3 0

2 years ago

Given the following linear function, sketch the graph of the function and find the domain and range.

Fantom [35]

1. To sketch the function f(x) = (2/3)x - 3, we first need to find two points that we can later join to sketch the line, for example the x- and y-intercepts.

a) The x-intercept occurs when f(x) = 0, so if f(x) = 0, then:

f(x) = (2/3)x - 3

0 = (2/3)x - 3

3 = (2/3)x (Add three to both sides)

3*(3/2) = x (Multiply both sides by 3/2)

9/2 = x

We have now found the x-intercept at (9/2, 0)

b) The y-intercept occurs when x = 0, so:

f(x) = (2/3)x - 3

f(0) = (2/3)*0 - 3

f(0) = -3

Now we know that the y-intercept is at (0, -3)

c) All that's left is to sketch the graph axes and label them, plot the two points, join them together using a ruler and label their coordinates.

2. The Domain is the range of x-values for which the function exists, and the Range is the range of y-values for which the function exists.

Since there haven't been any constraints specified, we can say that both the Domain and Range are (-∞, ∞), since the graph continues forever both along the x- and y-axis.

(Note that this isn't always the case and would change if, for example, the question stipulated that there was a domain of [0, 5] and you had to find the range. Then, you would calculate the value of y at each end of the domain (if x = 0, y = -3 and if x = 5, y = 1/3) - in my example, the range would thus be [-3, 1/3].)

7 0

3 years ago