Describe how both IPv4 and IPv6 access and utilize TCP as an upper-layer transfer protocol.

Computers and Technology

1 answer:

grin007 [14]3 years ago

6 0

Answer: Please see below as the answer is self-explanatory

Explanation:

For the TCP/IP protocol suite, the IP protocol is the Network (or Internet) layer (Layer 3 in the OSI model), and TCP is one of the possible options for the Transport Layer, (Layer 4 in the OSI model).

Now, how the transport layer is aware that the transport protocol to be used is TCP?

When the network layer receives a packet, reads the IP Header, processes it, and then, after stripping it from the packet, sends it to the immediate upper layer.

In the IP header, there is a field, that tells the network layer, which is the protocol that will take care of the packet payload once processed by the network layer.

This field, has different names in IPv4 and IPv6; It is called PROTOCOL in IPv4, and NEXT HEADER in IPv6.

It has a length of 8 bits, and the binary value included in it, identifies uniquely the type of upper-layer protocol to be used, being the same for the same protocol in both versions of IP protocol.

For TCP, it is 6 in binary: 00000110.

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The combined output will be option D which is

This porridge is too hot.

This porridge is just right!

Explanation:

As the complete question is not the given the complete question is found online and is attached herewith.

Now from the given attached code

As the temperature value is 180 which is more than 90 so the first loop is true and the first print out is

This porridge is too hot.

Now the temperature is cooled down using the formula such that the temperature reduced 100 degrees in the intervals of 20 now the temperature becomes 80. As it is greater than 70, thus the second if loop is not executed.

As the temperature is 80 this the next print out will be as

This porridge is just right!

So the combined output will be option D which is

This porridge is too hot.

This porridge is just right!