(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
Answer:
Step-by-step explanation:
-2x -3y = 5
4x + 3y = 17
2x = 22
x = 11
4(2) + 3y = 17
8 + 3y = 17
3y = 9
y = 3
(11,3)
Answer:
The median number of interceptions in 1998 is equal to the third quartile of 2008.
Step-by-step explanation:
i guessed pls mark brainliest
Answer:
One order pair is
(
2,0)
Step-by-step explanation:
What ordered pairs are the options?
Pick a value for
x
and solve for
y
. Or find the intercepts.
If
x
=
2
, then:
y
=
2
−
2
⇒
y
=
0
So we have
(
2
,
0
)
If
x
=
0
, then:
y
=
0
−
2
⇒
y
=
−
2
Here we have
(
0
,
−
2
)
You can simply use
0
for both
x
and
y
(intercept) to get the same answer.
Answer:
no value of X so no answer
Step-by-step explanation:
