Answer:
(6, 2), (0, -2), (-3, -4)
Step-by-step explanation:
The intercepts are clearly (0, -2) and (3, 0). This eliminates the bottom two choices.
Both of these are listed in the upper left choice, but the third point there, (-6, -5), is not on the graph. This leaves only the upper right choice. Checking the remaining two points in that choice, (6, 2) and (-3, -4), confirms they are both on the graph.
May you give answer choices please.
Answer:
k is the option that makes sense
By using the AAA congruence property of Triangles, △aec≅△deb is proved
It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad
Also, it is given that,
ca ║db
We need to prove that, △aec≅△deb
Then we'll use AAA congruence property of Triangles to prove the situation
As ca ║db
then, ∠cae = ∠ebd (Alternate angles)
∠ace = ∠edb (Alternate angles)
and ∠aec = ∠deb (common angles)
Thus, by AAA congruence property, △aec≅△deb
Hence, proved
To learn more about, congruence property, here
brainly.com/question/2039214
#SPJ4
If it's 4 less than 2 times a number if would be
<span>2x - 4</span>
