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alina1380 [7]
3 years ago
11

4,12,16,48,52,156,160,_,_,_ find the next 3 numbers

Mathematics
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

480, 484, and 1452

Step-by-step explanation:

To find the next three numbers to the sequence, we would first have to find the pattern between all of the numbers. Lets look at the first two numbers. 12 is 4 multiplied by 3. 12 is also 4 added with 8. Lets see if any of these work for the other sets of numbers:

4 × 3 = 12   Good

4 + 8 = 12   Good

12 × 3 ≠ 16

12 + 8 ≠ 16

16 × 3 = 48   Good

16 + 8 ≠ 48

48 × 3 ≠ 52

48 + 8 ≠ 52

52 × 3 = 156   Good

52 + 8 ≠ 156

156 × 3 ≠ 160

156 + 8 ≠ 160

So from what we can see, only the multiply by 3 pattern works more than once, but it seems to only work every other pair of numbers. The pattern may be alternating, so lets try to find the pattern between the other pairs of numbers that the multiply by 3 pattern does not work for.

12 and 16

48 and 52

156 and 160

You should be able to see here that the pattern for these pairs of numbers is adding 4. So the pattern for the entire set of numbers alternates between multiply by 3 and add 4. Knowing this, we can find the next three numbers

So right before the first missing number there was an add 4. So this time we must multiply by 3 to find the first missing number.

160 × 3 = 480

So the first missing number is 480. Now we add 4 to find the next missing number.

140 + 4 = 484

So the second missing number is 484. Now to find the final missing number, we multiply by 3 again.

484 × 3 = 1452

So the third missing number is 1452.

The three missing numbers are 480, 484, and 1452.

I hope you find my answer and explanation to be helpful. Happy studying.

seropon [69]3 years ago
3 0

Answer:

Vigil for an hour and two

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Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph
Dennis_Churaev [7]

ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


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f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


f(-3)=81+27-63-39-6



f(-3)=6-6



f(-3)=0


Also




f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6



f(2)=16-8-28+26-6



f(2)=6-6



f(2)=0


This implies that  


x-2 and x+3 are factors of



f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6


f(-4)=150\:>0



-3\le x \le 1


f(0)=-6\:


1\le x\le 2


f(1.5)=-0.56\:



x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



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