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3 years ago

14

Solve the proportion 2/43 = j/13

1 answer:

xz_007 [3.2K]3 years ago

4 0

The Answer is:

j = 26/43

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How did u get 4/3. Because I’m confused

Svet_ta [14]

What’s the original question and I can help!

5 0

3 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

Please help me thank you I’ll mark Brainly

Phoenix [80]

Answer:

276

Step-by-step explanation:

60 feet plus 3 is 63, 63 times 2 is 126, 126 +150 is 276

6 0

3 years ago

Which of the following is equivalent to 1 cup

kipiarov [429]

1 cup=16 tablespoons

6 0

3 years ago

Read 2 more answers

The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consume

AfilCa [17]

Answer:

Yes. The male and female consumers differ in the amounts they spend.

Step-by-step explanation:

We can express the null and alternative hypothesis as:

$H_0: \mu_m=\mu_w\\\\H_1: \mu_m\neq\mu_w$

It is assumed a significance level of 0.05.

The standard deviation of the difference of means is calculated as:

$s=\sqrt{\frac{s_m^2}{n_m} +\frac{s_w^2}{n_w} } =\sqrt{\frac{35^2}{40} +\frac{20^2}{30} } =\sqrt{30.625+13.333} =\sqrt{43.958} =6.63$

The test statistic is

$t=\frac{(M_m-M_w)-0}{s}=\frac{135.67-68.64}{6.63}=10.11$

The degrees of freedom are:

$df=n_1+n_2-2=40+30-2=68$

The P-value for t=10.11 is P=0, so it is smaller than the significance level. The null hypothesis is rejected.

We can conclude that male and female consumers differ in the amounts they spend.

5 0

4 years ago