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vichka [17]
3 years ago
6

What is negative 3÷0

Mathematics
2 answers:
Gnoma [55]3 years ago
4 0
Division by zero is undefined. That is a impossible question  
trapecia [35]3 years ago
3 0

you cann`t divide by 0 , it is not possible ,
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The product of odd numbers is always even true or false ?
likoan [24]

Answer:

false

Step-by-step explanation:

let's say we have two odd numbers

2k+1 and 2t+1

(2k+1)(2t+1)\\\\=4kt+2k+2t+1\\\\=2(2kt+k+t)+1

so we see it's odd

6 0
3 years ago
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An Environmental Club collected 100 pounds of aluminum cans to recycle. 1 point
MissTica

Answer:

well, there are 52 weeks in a year, so if you just multiply the pounds of cans by the amount of years, you get 1,300

Step-by-step explanation:

*sigh*

4 0
3 years ago
What is the slope? 18,4.5/20,5
jarptica [38.1K]

Answer:

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Step-by-step explanation:

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3 years ago
Consider the function: f(x) = 2x^2 - 1.5x - 5 and its graph.
Dominik [7]

Answer:

f(x) = -4x² + 19x - 18

Step-by-step explanation:

f(x) = 2x^2 - 1.5x - 5

i) If it is translated 2 units in the positive x direction, therefore we use f(x-2)

y=f(x-2) = 2(x-2)^2 - 1.5(x-2) - 5\\y = 2(x^2-4x+4) - 1.5x+3 - 5\\y=2x^2-8x+8-1.5x+3-5\\y=2x^2-9.5x+6

f(x) = 2x² - 9.5x + 6

If it is then translated 3 units in the positive y, we add 3 to the input function to get:

y=f(x)+3=2x^2-9.5x+6+3\\y = 2x^2-9.5x+9

ii) stretched vertically by a factor of 2, we multiply the function by 2 to get:

y =2( 2x^2-9.5x+9) = 4x^2-19x+18\\y= 4x^2-19x+18

iii) reflected across the x-axis

we multiply the parent function by –1, to get a reflection about the x-axis.

y= -1(4x^2-19x+18)=-4x^2+19x-18\\y=f(x)=-4x^2+19x-18

5 0
3 years ago
Iris Setosa is a beautiful wildflower that is found in such diverse places as Alaska, the Gulf of St.
monitta

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: To finish the sample you need the term, 1.5 Then the sample is done!

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

8 0
3 years ago
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