-3n < 81...divide both sides by -3, change the inequality sign
n > -81/3
n > - 27 <==
** in an inequality, when dividing/multiplying by a negative number, the inequality sign changes
<em>4</em><em>0</em><em>+</em><em>40</em><em>+</em><em>40</em>
<em>6.80</em><em>÷</em><em>2</em>
<em>and</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>do</em><em> </em><em>this</em><em> </em>
<em>you</em><em> </em><em>will</em><em> </em><em>end</em><em> </em><em>up</em><em> </em>
<em>getting</em><em> </em><em>your</em><em> </em><em>answers</em><em> </em>
Answer:
The Alans's average for the course is 84.5
Step-by-step explanation:
We are given
There are 4 tests, A Term paper and a Final examination.
Score = 92, 78, 82, 90.
Term paper score = 80
Final examination score = 86
Weighted mean = ∑ w.f/∑w
also the sum of all the weights is 100% = 1
weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1
= 51.3 + 33.2
= 84.5
Therefore the Alans's average for the course is 84.5
Answer & Step-by-step explanation:
In the problem, we are given an equation. h(t) = -20 + 11t
In the equation, t represents an unknown value. So, if we are given a number that is in the replacement of t, then we can plug that number in to where t is at.
t = 11
h(11) = -20 + 11(11)
h(11) = -20 + 121
h(11) = 101
So, h(11) is equal to 101
