The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
They all equal zero
Step-by-step explanation:
A number cannot equal itself times any number that isn't zero, unless it itself is zero.
Answer:
9 times
Step-by-step explanation:
first you do 14 - 2.75 which equals 11.25. you divide that number by 1.25 which equals 9 in total, getting you your answer
Answer:
Distributive property
Step-by-step explanation:
-3/4*5/4-(-6/7)*(-3/4)
-15/16-(18/28)
-15*7-18*4/112
-105-72/112
-177/112
