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stealth61 [152]

3 years ago

11

Simplify the expression -4(x - 5)

1 answer:

STatiana [176]3 years ago

6 0

Answer:

-4x+20

Step-by-step explanation:

$-4(x - 5)\\\\=-4x-4(-5)\\\\=-4x+20$

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- Joy and John MacAllister have agreed to purchase a house for $79,900. First

taurus [48]

Answer:

Step-by-step explanation‎:

6 0

3 years ago

Please help i need an answer

Neko [114]

Answer:

see below

Step-by-step explanation:

A filled dot means the function is defined there. An open dot means it is not defined there. A portion of the graph with no line or curve means the function is undefined there.

The domain is the horizontal extent of the function definition. Here, the function is defined between -8 and +8 with a hole between 3 and 4. The appropriate answer is the one that has two pieces. See the attachment.

6 0

4 years ago

Fancy goldfish x cost $3 each and common goldfish y cost $1 each.Graph the function y=20-3x to determine how many of each type o

aniked [119]

The pairs of goldfish Tasha can buy for $20 are $(0,20), (1,17), (2,14),$

$(3,11),(4,8),(5,5),and (6,2)$

Step-by-step explanation:

To find the how many type of goldfish that Tasha can buy for $20 is the set of positive ordered pairs.

Let x denote the number of fancy goldfish.

Let y denote the number of common goldfish.

To find how much goldfish can Tasha buy for $20 is to substitute the value for x in the equation $y=20-3x$

Now, substituting $x=0$ in $y=20-3x$ , we get,

$y=20$

The ordered pair is $(0,20)$

Similarly, substituting $x=1$ ,

$y=20-3(1)\\y=20-3\\y=17$

For $x=2$ ,

$y=20-6\\y=14$

For $x=3$ ,

$y=20-9\\y=11$

For $x=4$ ,

$y=20-12\\y=8$

For $x=5$ ,

$y=20-15\\y=15$

For $x=6$ ,

$y=20-18\\y=2$

Thus, the pairs of goldfish Tasha can buy for $20 are $(0,20), (1,17), (2,14),$ $(3,11),(4,8),(5,5),and (6,2)$

4 0

3 years ago

When X=18, Y=14. Find the value of x when y=42.<br><br> A) 32<br> B) 18<br> C) -18 <br> D) 54

Karolina [17]

Answer:

D)54

Explanation:

hope this helps you...

4 0

3 years ago

Consider the following IP problem:

Liono4ka [1.6K]

Answer:

$(3,0)$

Step-by-step explanation:

The integer points which fall in the common region bounded by the lines are

$(0,2),(2,3),(3,0)$

Since, one of the points is $(2.22...,3.11....)$ we round it to $(2,3)$

If we round up then the point will be $(3,4)$ which does not fall in the bounded region.

Also $x_1\geq 0$ and $x_2\geq 0$ no negative values are considered.

Applying in the values in the LP problem $Z=5x_1+x_2$

$Z=5\times 0+2\\\Rightarrow Z=2$

$Z=5\times 2+3\\\Rightarrow Z=13$

$Z=5\times 3+0\\\Rightarrow Z=15$

So, the LP problem is maximum at point $(3,0)$ .

7 0

3 years ago