Answer:
It would be the 4th one and the last one I think
Step-by-step explanation:
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
You can also multiply the decimals by a multiple of 10 to turn them I to whole numbers. Just make sure you multiply them both by the same multiple of 10 and divide them back before you write your answer!
Answer:
I believe it is 5.25
Step-by-step explanation:
if you multiply 3 and 7 then divide by 4 you will get 1 fourth of 21 which is 5.25 !!
Ht of ceiling = 10 ft which is two-thirds of living rm ceiling
Ht of living rm ceiling = 2/3x = 10 ft
2/3h = 10 ft
2/3h times 3/2 to solve for h = 10 times 3/2
h = 30/2
h = 15 ft