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Serggg [28]
3 years ago
14

How do i go about identifying the slope & y-intercept in y = -3/4 x -7?

Mathematics
1 answer:
choli [55]3 years ago
5 0
Y=mx+b the m is your slope. Here the slope would be -3/4. The b is your y-intercept which is -7.
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A rectangle is removed from a right triangle to create the shaded region shown below. Find the area of the shaded region.
irina [24]

Answer:

I can't tell what the triangle is

Step-by-step explanation:

8 0
3 years ago
Convert please
dezoksy [38]
<h3>Answer:</h3>
  1. 3,8 kg
  2. 750 g
  3. 7,47 g
<h3>Step-by-step explanation:</h3><h3>3800 g => kg</h3>

(3800 ÷ 1000) kg

= 3,8 kg

<h3>¾ kg => g</h3>

(3 ÷ 4)kg × 1000

= 0.75 × 1000

= 750 g

<h3>7470 g => kg</h3>

(7470 ÷ 1000) kg

= 7,47 kg

4 0
3 years ago
Needed quickly like asap
Artemon [7]
It is 18/20 and in simplest form it is 9/10.


Steps:
1.You have to add all the shirts, 2+7+11. This is 20, this will become your denominator

2. See what portion is NOT BLACK, the non black at 7 and 11, once you add these it becomes 18. 18 is now your numerator.

3. You now have the fraction 18/20 which you can simplify into 9/10




Hope this helps :)
4 0
3 years ago
Please do elimination method 2x-9y=-36 <br> -14x+18y=-18
Varvara68 [4.7K]

Answer:

The solution to the system of equations will be:

x=9,\:y=6

Step-by-step explanation:

Given the system of equations

\begin{bmatrix}2x-9y=-36\\ -14x+18y=-18\end{bmatrix}

Multiply 2x-9y=-36 by 7

14x-63y=-252

so the system of equations becomes

\begin{bmatrix}14x-63y=-252\\ -14x+18y=-18\end{bmatrix}

Adding both equations

-14x+18y=-18

+

\underline{14x-63y=-252}

-45y=-270

solve -45y = -270 for y

-45y=-270

divide both sides by -45

\frac{-45y}{-45}=\frac{-270}{-45}

Simplify

y=6

For 14x-63y = -270 plug in y = 6

14x-63\cdot \:6=-252

14x-378=-252

Add 378 to both sides

14x-378+378=-252+378

Simplify

14x=126

Divide both sides by 14

\frac{14x}{14}=\frac{126}{14}

Simplify

x=9

Therefore, the solution to the system of equations will be:

x=9,\:y=6

7 0
3 years ago
The p-value for a one-sided t-test is 0. 10. If the test had been two-sided, what would the p-value have been?.
Dmitriy789 [7]

Considering the one-sided p-value, the p-value for a two-sided test would be of 0.20.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows:

  • For a left-tailed test, it is the area under the normal curve to the left of z, which is the p-value of z.
  • For a right-tailed test, it is the area under the normal curve to the right of z, which is 1 subtracted by the p-value of z.
  • For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is 2 multiplied by 1 subtracted by the p-value of z, which means that <u>the p-value for a two-tailed test is </u><u>twice </u><u>the p-value of a one-tailed test</u>.

In this problem, for the one-tailed test, the p-value is of 0.1, hence the p-value for a two-sided test would be of 0.20.

You can learn more about p-values at brainly.com/question/13873630

4 0
2 years ago
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