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Anna11 [10]
3 years ago
5

The amount of money a student spends at the end of year carnival can be represented by the given equation. Graph the equation on

the coordinate plane.

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer: See the graph attached.

Step-by-step explanation:

The Slope-intercept form of the equation of the line is:

y=mx+b

Where "m" is the slope and "b" is the intersection of the line with the y-axis.

Given the equation y=\frac{1}{2}x+3, you can identify that:

m=\frac{1}{2}\\\\b=3

The line intercepts the y-axis when x=0, therefore, you can know that the line passes through the point:

(0,3) → Point of intersection with the y-axis.

Now, substitute y=0 and solve for "x" to find the point of intersection with the x-axis:

0=\frac{1}{2}x+3\\\\-3=\frac{1}{2}x\\\\(-3)(2)=x\\\\x=-6

Now, you know that the line also passes through the point:

(-6,0) → Point of intersection with the x-axis.

Draw the a line that passes through these points.

Therefore, you get the graph attached.

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Approximate the value of each of the irrational numbers below to the nearest thousandth.
Marta_Voda [28]

ANSWER

\sqrt{13}  = 3.606

to the nearest thousandth.

EXPLANATION

The given irrational number is

\sqrt{13}

We use the calculator to evaluate this to obtain,

\sqrt{13}  = 3.605551...

To round to the nearest thousandth means we are rounding to 3 decimal places.

The third decimal place is 5.

The next number is 5 so we round up.

\sqrt{13}  = 3.606

4 0
3 years ago
Solve the equation x^2-4x+85=0
lara [203]
Can't factor
use quadratic
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
1x^2-4x+85=0
a=1
b=-4
c=85

x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}
x=\frac{4+/- \sqrt{16-340} }{2}
x=\frac{4+/- \sqrt{-324} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}
remember that √-1=i
x=\frac{4+/- i(\sqrt{324}) }{2}
x=\frac{4+/- i(18) }{2}
x=2+/-9i

x=2+9i or x=2-9i
3 0
3 years ago
How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
2 years ago
Which values from the given replacement set make up the solution set of the inequality? 2b≥6;
Bingel [31]
The answer is A because the variable can’t be no lower than 3 and every other answer has 2 in it. 2•(3) is equal to 6 and 2•(4) is greater than 6 which correlates with the sign (greater than or equal to).
5 0
3 years ago
Problem: Try this one on your own.
Anna [14]

Answer:

iiiii

Step-by-step explanation:

8 0
2 years ago
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