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deff fn [24]
3 years ago
6

Can anyone help me I was self isolating when my class was taught this and I can't get in contact with my teacher

Mathematics
2 answers:
Ghella [55]3 years ago
6 0

Answer:

1. x=3 y=2 ---- 2. x=5 y=1 ---- 3. x=2 y=4 ---- 4. x=3 y=2 ---- 5. x=5 y=1 ---- 6. x=5 y=5

Step-by-step explanation:

1. 3x3=9, 2x2=4, 9+4=13

2. 2x5=10, 5x1=5, 10+5=15

3. 4x2=8, 2x4=8, 8+8=16

4. 3+(2x2)=7

5. 3x5=15, 10x1=10, 15-10=5

6. 3x5=15, 3x5=15, 15+15=30

I hope this helps, I'm so sorry if it's wrong

Aleonysh [2.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

3x +2y = 13   -----------------(i)

x + 2y = 7    ----------------(ii)

Multiply the equation (ii) by (-1) and then add.

(i)              3x + 2y = 13

(ii)*(-1)      <u>-x    - 2y = -7 </u>        {Now, add and y will be eliminated}

                 2x       = 6

                        x = 6/2

x = 3

Plug in x = 3 in equation (i)

3*3 + 2y = 13

  9 + 2y = 13

         2y= 13 - 9

         2y = 4

           y = 4/2

y = 2

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Answer:

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Step-by-step explanation:

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kozerog [31]
Hello!
So the following would be your equation.
3(x+5)-10= 29
Your first step would be to use the Distributive Property based upon PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction). Since we have Parenthesis, we distribute first.
3(x+5)-10=29
^ ^
——————
So, your new equation would be—
3x+15-10=29
Now, you need to combine like terms—
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3x+5=29
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Therefore your new equation is—
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Now you need to move the constants (5,29) to one side of the equal sign. To do this, you would use the Subtraction Property of Equality and rid the 5–
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Your equation is now—
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