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gulaghasi [49]
3 years ago
6

A group of students is given a 10 by 10 grid to cut into individual unit squares. The challenge is to create two squares using a

ll of the unit squares. Their teacher states that after the two new squares are formed, one should have a side length two units greater than the other.Which equation represents x, the side length of the greater square?
Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

8 is the side length of the greater square.  100=x^2+(x-2)^2

Step-by-step explanation:

64+36=100

8 squared plus 6 squared equals 10 squared

8 is 2 more than 6

100=x^2 +y^2

x-y=2

100=x^2+(x-2)^2

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Someone please help me answer this question ​please and thank you.​
fenix001 [56]

Students collect cards with equivalent mathematical or verbal expressions on them to make books of cards.  A book is a group of 3 or 4 cards with either equivalent mathematical expressions or equivalent verbal expressions on them. When a player has at least 3 matching cards, he/she may lay down the book of cards.  The object of the game is to be the first to get rid of all the cards in your hand.

 

Preparation:  The teacher should print enough decks of cards so that one deck per group of 4 students can be distributed.

Shuffle the cards and deal out 7 cards to each player.  Place the remaining cards in a pile (the draw pile) in the center of the table.  Turn one card over to create the discard pile.

On his/her turn, each player will:

Either draw a card from the draw pile OR pick up the top card of the discard pile.  (A player may only pick up the top card of the discard pile if by doing so it creates a book that the player can lay down immediately or it is a card that can be added to an existing book on the table.) 

The player then examines his/her hand to see if there are any sets of three or four that can be laid down. If so, the cards are laid down on the table face up.

If the player does not have any groups to lay down, he/she may lay down a single card if that card can be added to another player’s book that has been laid on the table previously. 

If the player can not put down a book or a single card to add to an existing book, then the player’s turn is over.

At the end of each turn the player must place a card on the discard pile.  If this is the last card in his/her hand, then he/she is the winner!

Play moves to the left in a similar fashion until all the cars have been played or no other cards remain to be drawn and no player can go out.  At that point, the player with the least number of cards in his/her hand is the winner.

Variation:

Students collect cards to make books but can only add a card to a book they have placed on the table themselves.  At the end of the game, the player with the most books is the winner.

7 0
3 years ago
How much interest is earned on $300 at 6% for 6 years?
miskamm [114]

Answer:

108 dollars

Step-by-step explanation:

First, let's convert 6% to a decimal.

We get 0.06 because we multiplied (or divided by 100) it by 1/100.

Now, let's do 0.06 * 300 to get interest on one year. This equals to 18$

Let's now do 18 * 6 to get

108 dollars

7 0
3 years ago
Find the lateral and surface area of each cone
Sophie [7]

Answer:

\large\boxed{L.A.=153\pi\ mm^2}\\\boxed{S.A.234\pi\ mm^2}

Step-by-step explanation:

The formula of a lateral area of a cone:

L.A.=\pi rl

r - radius

l - slant height

The formula of a surface area of a cone:

S.A.=\pi r^2+\pi rl

We have r= 9mm and l = 17mm. Substitute:

L.A.=\pi(9)(17)=153\pi\ mm^2

S.A.=\pi(9^2)+153\pi=81\pi+153\pi=234\pi\ mm^2

7 0
3 years ago
Which pair of numbers, if included in this set, would not change the median?
sattari [20]

Answer:

A)

Step-by-step explanation:

Order the set first

27, 28, 35, 37, 43, 47

Median now is: 36 (which is the mean between 35 and 37, the two central numbers )

If you add A) 35,50 then you will still have to compute the mean between 35 and 37 in order to find the median, because you have:

27,28,35,35,37,43,47,50

7 0
4 years ago
Read 2 more answers
Will mark brainliest if right
azamat

Answer: 5x^2 + 3x + 1

Step-by-step explanation:

1.) Put the two equations together into an addition problem.

<em>3x^2 + 4x + 2x^2 - x + 1</em>

2.) Combine like terms.

<em>3x^2 + 2x^2 = 5x^2</em>

<em>4x - x = 3x</em>

<em>1 = 1</em>

3.) Order the like terms together.

<em>5x^2 + 3x + 1</em>

8 0
3 years ago
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