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gulaghasi [49]
3 years ago
6

A group of students is given a 10 by 10 grid to cut into individual unit squares. The challenge is to create two squares using a

ll of the unit squares. Their teacher states that after the two new squares are formed, one should have a side length two units greater than the other.Which equation represents x, the side length of the greater square?
Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

8 is the side length of the greater square.  100=x^2+(x-2)^2

Step-by-step explanation:

64+36=100

8 squared plus 6 squared equals 10 squared

8 is 2 more than 6

100=x^2 +y^2

x-y=2

100=x^2+(x-2)^2

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Murrr4er [49]
7 times 48 is 336
7 times 47 is 329
332/7= 47.4
7/332=.021
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ASHA 777 [7]

stranger things A jewellery shop is having a sale.

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% of the original price.

b) Work out the original price of this ring.A jewellery shop is having a sale.

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A brace

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This is 40% of the original price.

b) Work out the original price of this ring. yeey this is important

3 0
3 years ago
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Nine times the quantity one-fourh plus a number is six less than the number divided by three
gregori [183]
Let the number be x.
9(1/4)+x=x/3+6
Simplify.
2.25+x=x/3+6
-6 -6
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-11.25+3x=x
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7 0
3 years ago
Simplify -5^5 ÷ -5^-6
Tpy6a [65]

Answer:

5^11

Step-by-step explanation:

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5 0
3 years ago
Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation
Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

                         f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

                           A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2

Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.

Download docx
3 0
3 years ago
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