Answer:
Step-by-step explanation:
T=V/6-5
T+5=V/6
6(T+5)=V
V=6T+30
Answer:
26.2 units
Step-by-step explanation:
We are given the points/vertices
A(6, 3),
B(6, - 2) , and
C(- 4, 3)
Step two
Let us find the distances between the given points/vertices
A-B =A(6, 3) to B(6,-2)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6-6)²+(-2-3)²)
d=√(-2-3)²)
d=√(-5)²)
d=5 units
B-C=B(6, - 2) to C(-4, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((-4-6)²+(3+2)²)
d=√(-10)²+(5)²)
d=√100+25
d=√125
d=11.2 units
C-A=C(-4, 3) to A(6, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6+4)²+(3-3)²)
d=√(10)²
d=√100
d=10 units
Hence the perimeter is 5+11.2+10
P=26.2 units
A+b+c = 131
b = 7 + 2a and c = a - 12
so a + 7+2a + a-12 = 131
then 4a -5 = 131
then 4a = 136
and a = 34....so b= 75 and c = 22....check 34+75+22=131√
Answer:
The answer to your question is: B and D are correct
Step-by-step explanation:
Remember that the sum of the internal angles in a triangle equals 180°.
The sum of supplementary angles equals 180°
Then
(6x + 1) + (4x + 5) + [180 - (8x + 30)] = 180
6x + 1 + 4x + 5 + [180 - 8x - 30] = 180
10x + 6 + 150 - 8x = 180
2 x = 180 - 156
2x = 24
x = 24/2
x = 12
∠JKL = 4(12) + 5 = 48 + 5 = 53
∠KJL = 6(12) + 1 = 72 + 1 = 73
∠KLJ = 180 - 73 - 53 = 54
∠KLM = 126
