Recursive equation would be f(x+1) = f(x) - 25 with f(0) = 300
Explicit equation would be f(x) = -25x + 300
And graph would looks like this:
a) Local maximum values of g are: 0 and 3
b) The values at which g has local maximum are : -2 and 2
<h3>What is a maximum point?</h3>
A maximum point is the point at which the gradient of the curve changes from positive to negative.
Analysis:
The inverted v-curves all have maximum values and they are two.
The one at x = -2 and the one at x = 2 for in both cases their maximum values are y = 0 and y = 3 respectively.
Learn more about minimum and maximum points: brainly.com/question/14993153
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Answer:
$10,500
Step-by-step explanation:
since his income is b/n $50,000 and $100,000, he pays 15%, (15/100)70,000=$10,500
Answer:
The scaled surface area of a square pyramid to the original surface area.
The scaled area of a triangle to the original area.
Step-by-step explanation:
Suppose that we have a cube with sidelength M.
if we rescale this measure with a scale factor 8, we get 8*M
Now, if previously the area of one side was of order M^2, with the rescaled measure the area will be something like (8*M)^2 = 64*M^2
This means that the ratio of the surfaces/areas will be 64.
(and will be the same for a pyramid, a rectangle, etc)
Then the correct options will be the ones related to surfaces, that are:
The scaled surface area of a square pyramid to the original surface area.
The scaled area of a triangle to the original area.
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
