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lana66690 [7]
3 years ago
7

There are 5 classes with 22 students per class ordering pizza. One pizza feeds 5 people. Which of the following is a good estima

tion of how many pizzas are needed?
Mathematics
2 answers:
Dominik [7]3 years ago
7 0

Answer:

22 pizzas

Step-by-step explanation:

<h2><u>Which of the following is a good estimation of how many pizzas are needed?</u></h2>

there are 5 classes , 22 people <em>per class</em>

hence total number of people in all 5 classes are:

5*22 = 110

one pizza feeds 5 people hence :

110/5

= <u>22 pizzas</u>

exis [7]3 years ago
6 0

Answer:

4.4

Step-by-step explanation:

22/5=4.4

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Answer:

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In a recent contest, the mean score was 210 and the standard deviation was 25. a) Find the z-score of John who scored 190 b) Fin
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Answer:

a) Z = -0.8

b) Z = 2.4

c) Mary's score was 241.25.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 210, \sigma = 25

a) Find the z-score of John who scored 190

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 210}{25}

Z = -0.8

b) Find the z-score of Bill who scored 270

Z = \frac{X - \mu}{\sigma}

Z = \frac{270 - 210}{25}

Z = 2.4

c) If Mary had a score of 1.25, what was Mary’s score?

Z = \frac{X - \mu}{\sigma}

1.25 = \frac{X - 210}{25}

X - 210 = 25*1.25

X = 241.25

Mary's score was 241.25.

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3 years ago
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