<span>X^2+x-2/1-x^2 ÷ 2x^2-6x-20/x^2-4x-5
(x + 2)(x - 1) (x - 5)(x + 1)
= ------------------- * ---------------------
(1 + x)(1- x) 2(x + 2)(x - 5)
</span> (x - 1)
= ----------
2(1- x)
- (1 - x)
= -------------
2(1 - x)
= -1/2
answer
-1/2
∠1 and ∠3 complementary,
∠1 = ∠2,
so
∠1 and ∠2 complementary.
Answer : C.
Your numbers are 2, 3, 4.
The three consecutive numbers are x, x+1, x+2
The square of the first equals the third so x^2=x+2
Solve this quadratic as x^2-x-2=0
Factor into (x+1)(x-2)=0
So your answers are x=-1 and x=2
Since the question says they’re positive integers, use x=2
So the numbers are 2, 3, 4
Answer:
5 cm
7cm
Step-by-step explanation:
