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3 years ago

Help pleasee last attempt

Mathematics

1 answer:

Lelechka [254]3 years ago

3 0

I believe the answer is 240 m.

To find the area make sure you multiply the base and the width.

4x8=32

Then you have to multiply 32 by the height.

32x7.5=240

Hope this helps!!!

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A campground consists of 5 square campsites arranged in a line along a beach. The distance from the edge of a campsite to the wa

Anestetic [448]

To answer this question with the choices given, you would substitute the possible answers into your work for the base and the height of each dimension on the entire campground.

To find the length of the campground, you multiply each choice by 5 because there are 5 campsites.

For the width, you add each choice to 4.

Then you multiply the total length by the total width to see if your answer is 950 square yards.

See the attached picture for all the work.

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3 years ago

Combine like terms . Please help me I am an vacation and I don't know how to do this

Georgia [21]

2x^4
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3 years ago

Solving a trigonometric equation involving an angle multiplied by a constant

PIT_PIT [208]

In these questions, we need to follow the steps:

1 - solve for the trigonometric function

2 - Use the unit circle or a calculator to find which angles between 0 and 2π gives that results.

3 - Complete these angles with the complete round repetition, by adding

$2k\pi,k\in\Z$

4 - these solutions are equal to the part inside the trigonometric function, so equalize the part inside with the expression and solve for <em>x</em> to get the solutions.

1 - To solve, we just use algebraic operations:

$\begin{gathered} \sqrt[]{3}\tan (3x)+1=0 \\ \sqrt[]{3}\tan (3x)=-1 \\ \tan (3x)=-\frac{1}{\sqrt[]{3}} \\ \tan (3x)=-\frac{\sqrt[]{3}}{3} \end{gathered}$

2 - From the unit circle, we can see that we will have one solution from the 2nd quadrant and one from the 4th quadrant:

The value for the angle that give positive

$+\frac{\sqrt[]{3}}{3}$

is known to be 30°, which is the same as π/6, so by symmetry, we can see that the angles that have a tangent of

$-\frac{\sqrt[]{3}}{3}$

Are:

$\begin{gathered} \theta_1=\pi-\frac{\pi}{6}=\frac{5\pi}{6} \\ \theta_2=2\pi-\frac{\pi}{6}=\frac{11\pi}{6} \end{gathered}$

3 - to consider all the solutions, we need to consider the possibility of more turn around the unit circle, so:

$\begin{gathered} \theta=\frac{5\pi}{6}+2k\pi,k\in\Z \\ or \\ \theta=\frac{11\pi}{6}+2k\pi,k\in\Z \end{gathered}$

Since 5π/6 and 11π/6 are π radians apart, we can put them together into one expression:

$\theta=\frac{5\pi}{6}+k\pi,k\in\Z$

4 - Now, we need to solve for <em>x</em>, because these solutions are for all the interior of the tangent function, so:

$\begin{gathered} 3x=\theta \\ 3x=\frac{5\pi}{6}+k\pi,k\in\Z \\ x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z \end{gathered}$

So, the solutions are:

$x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z$

4 0

1 year ago

A cone has a diameter of 30 in. and a slant height of 17 in. What is the approximate volume of the cone?

Alex777 [14]

We need to find the height of the cylinder
pythagorean theorem
15 is the bottom leg (30/2=15)
17 is hypotonuse
b=height
15^2+b^2=17^2
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minus 225 both sides
b^2=64
sqrt both sides b=8

Vcone=(1/3)hpir^2
d/2=r=30/2=15
h=8
V=(1/3)8pi15^2
V=(1/3)8pi225
V=8pi75
V=600pi
aprox pi=3.14159256
V=1884.955536 in^3
round if nececary

7 0

3 years ago

How do u reduce 270/360 to lowest form

Ket [755]

You should simplify it using your Great Common Denominator which is 90
then, you divide each which is
270/90 out of 360/90
which gives u 3/4
and there goes your answer :)

4 0

3 years ago