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julia-pushkina [17]
3 years ago
5

Enrollment in a school has grown exponentially since the school opened. Below is a graph depicting this growth. Determine the av

erage rate of change from x = 0 to x = 20.
An exponential graph has time in years on the x axis and enrollments on the y axis. An upward rising curve begins at zero comma thirty and passes through twenty comma eighty.

0.4

2.5

5

30
Mathematics
2 answers:
tresset_1 [31]3 years ago
4 0

Answer:

2.5

Step-by-step explanation:

The average rate of the function f(x) from x=a to x=b is given by:

\frac{f(b)-f(a)}{b-a}

From the question, the exponential function goes through (0,30) and (20,80).

This implies that f(0)=30 and f(20)=80

Therefore the average rate of change from x = 0 to x = 20 is

=\frac{f(20)-f(0)}{20-0}

=\frac{80-30}{20}

=\frac{50}{20}=2.5

The second choice is correct

gavmur [86]3 years ago
3 0

Answer:

12.5

Step-by-step explanation:

if you divide 100 by 8, it gives you 12.5 & that is the rate of change for  x = 0 to x = 8.

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Jake drew a kite the sketch below of a kite that he wants to make.
Kipish [7]

Answer:

1/2 (40×60)

Step-by-step explanation:

area of kite = 1/2 × diagonal 1 × diagonal 2

3 0
3 years ago
Given: The coordinates of isosceles trapezoid JKLM are J(-b, c), K(b, c), L(a, 0), and M(-a, 0). Prove: The diagonals of an isos
In-s [12.5K]
We have to find the lengths of the diagonals KM and JL:
d ( KM ) = √ (( - a - b )² + ( 0 - c )²) = √ (( a + b )² + c² )
d ( JL ) = √ ( ( a - ( - b ) )² + ( 0 - c )²) = √ ( ( a + b )² + c² )
So the lengths of the diagonals KM and JL are congruent.
The lengths of the diagonals of the isosceles trapezoid are congruent.   
6 0
3 years ago
Read 2 more answers
A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An
Gnom [1K]
I would solve this using tangents.  Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
tan A = \frac{h+70}{40}  , tan B = \frac{70}{40}

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
tan (A-B) = \frac{tanA - tanB}{1+tan A  tan B}
Plug in what we know:
tan(9) = \frac{ \frac{h+70}{40} -  \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}
tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}
h = \frac{650 tan(9)}{4-7 tan(9)}
h = 35.6
7 0
3 years ago
GUYS HELP ME PLS. Tina is standing at the bottom of a hill. Matt is standing on the hill so that when Tina's line of sight is
Pie

Answer:

71°

Step-by-step explanation:

The angle of elevation of the hill can be obtiaed using trigonometry :

Given

the opposite length = 14.5 feets

Adjacent = 5 feets

The angle of elevation vabnbe obtained using :

Tan θ = opposite / Adjacent

Where θ = angle of elevation

Tan θ = 14.5 / 5

Tan θ = 2.9

θ = tan^-1(2.9)

θ = 70.97 = 71°

3 0
3 years ago
Aziza has a triangle with two sides measuring 11 in. and 15 in. She claims that the third side can be any length as long as it i
irina [24]

Answer:

Aziza’s claim is incomplete. The third side must be between 4 in. and 26 in.

Step-by-step explanation:

With the Triangle Inequality Theorem, saying that the sum of lengths of any two sides of a triangle is greater than the length of the third side. With this we can develop two inequalities:

11 + 15 > x

26 > x

rewrite this as x < 26

11 + x > 15

x > 15 - 11   Subtract 11 from both sides

x > 4

Therefore, the third side can be anywhere greater than 4 inches and less than and less than 26 inches.

4 <  x < 26

4 0
3 years ago
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