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gladu [14]
4 years ago
14

279÷24=? Write your answer as a whole number and remainder.

Mathematics
2 answers:
Anika [276]4 years ago
8 0

Answer:

the answer is 11.625 so it is <u><em>12</em></u>

Step-by-step explanation:


Ira Lisetskai [31]4 years ago
5 0

Answer:

the answer is 11.625

Step-by-step explanation:


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Trevor spent $27 and now has no money left. What did he have before his purchase
Sav [38]

Answer:$27

Step-by-step explanation:

x-27=0

0+27=27

27-27=0

8 0
3 years ago
An observer at the top of a tower of height 20m sees a man due East of him at an angle of depression of 27°. He sees another man
kotegsom [21]

Answer:

  • 52.35 m

Step-by-step explanation:

<em>Refer to picture.</em>

Let the distance to men are x and y and the distance between them is d.

The angle of depreciation is 27° and 30°, hence top angle of the triangle is 63° or 60°.

<u>Find the distance from the tower to men:</u>

  • x = 20 tan 63° = 39.25 m
  • y = 20 tan 60° = 34.64 m

<u>The distance between men is:</u>

  • d = \sqrt{x^2+y^2} =\sqrt{39.25^2+34.64^2} = 52.35m

<em>Note, all numbers are rounded</em>

8 0
3 years ago
(6m^3 -16m^2 + 15m - 40) / (2m^2 + 5)
Helen [10]
        6m3 - 16m2 + 15m - 40<span> Simplify ————————————————————— 2m2 + 5 </span>Checking for a perfect cube :

<span> 4.1 </span>  <span> 6m3 - 16m2 + 15m - 40</span>  is not a perfect cube 

Trying to factor by pulling out :

<span> 4.2 </span>     Factoring: <span> 6m3 - 16m2 + 15m - 40</span> 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  15m - 40 
Group 2: <span> -16m2 + 6m3</span> 

Pull out from each group separately :

Group 1:   (3m - 8) • (5)
Group 2: <span>  (3m - 8) • (2m2)</span>
               -------------------
Add up the two groups :
              <span> (3m - 8)  • </span><span> (2m2 + 5)</span> 
<span>Which is the desired factorization</span>

<span>3m-8 is the answer</span>

4 0
3 years ago
What is an algebraic expression for the height H increased by 6 inches
borishaifa [10]
H+6 I believe is the answer
6 0
4 years ago
Read 2 more answers
What is the possible arrangement for 22 students
lord [1]

\bf \stackrel{Permutations}{_nP_r=\cfrac{n!}{(n-r)!}}~\hspace{6em}\stackrel{\textit{22 units arranged in groups of 22}}{_{22}P_{22}=\cfrac{22!}{(22-22)!}} \implies _{22}P_{22}=\cfrac{22!}{0!} \\\\\\ _{22}P_{22}=\cfrac{22!}{1}\implies _{22}P_{22}=22!\implies _{22}P_{22}=1124000727777607680000

8 0
4 years ago
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