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3 years ago

4(x+7)=9(x-1)+22 solve for x

Mathematics

1 answer:

ira [324]3 years ago

5 0

Answer:

x = 3

Step-by-step explanation:

4(x+7)=9(x-1)+22

Begin solving for x by performing the indicated multiplication:

4x + 28 = 9x - 9 + 22

Combine the x terms:

28 = 9x - 4x - 9 + 22

28 = 5x + 13

Subtracting 13 from both sides isolates 5x:

15 = 5x. Then x = 3

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3 years ago

The volume code of a cube is given by s to the third power, where s is this side length of the cube. What is the difference of t

yKpoI14uk [10]

Answer:

61 m^3

Step-by-step explanation:

The difference in volume is (5 m)^3 - (4 m)^3, or (125 - 64) m^3, or

61 m^3

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3 years ago

Read 2 more answers

Can someone pls. help me with this, the instruction says "Find the Unknown length marked on the following figure. Round all the

coldgirl [10]

Answer:

The length of diagonal d is 14.1421 cm

Step-by-step explanation:

We are given square

Length of side of square = 10 cm

We need to find the length of diagonal d

To find diagonal of square, the formula used is:

$Diagonal\: of\: square=s\sqrt{2}$

where s is length of side of square.

Putting values of s and finding length of diagonal of square

$Diagonal\: of\: square=s\sqrt{2}\\Diagonal\: of\: square=10\sqrt{2}\\Diagonal\: of\: square=10(1.41421)\\Diagonal\: of\: square=14.1421\:cm$

So, The length of diagonal d is 14.1421 cm

3 0

3 years ago

What expression is equivalent to 1/5•1/5•1/5•1/5

lara31 [8.8K]

The expression will be 589/15

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3 years ago

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

3 years ago