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RoseWind [281]
3 years ago
9

PLEASE HELP!!!

Mathematics
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

x^2+y^2=25

Step-by-step explanation:

Recall the following Pythagorean Identity:

\sin^2(\theta)+\cos^2(\theta)=1

Let's solve the x equation for cos(t) and the y equation for sin(t).

After the solve we will plug into our above identity.

x=5cos(t)

Divide both sides by 5:

(x/5)=cos(t)

y=5sin(t)

Divide both sides by 5:

(y/5)=sin(t)

Now we are ready to plug into the identity:

\sin^2(t)+\cos^2(t)=1

(\frac{y}{5})^2+(\frac{x}{5})^2=1

\frac{x^2}{5^2}+\frac{y^2}{5^2}=1

Multiply both sides by 5^2:

x^2+y^2=5^2

This is a circle with center (0,0) and radius 5.

All I did to get that was compare our rectangular equation we found to

(x-h)^2+(y-k)^2=r^2

where (h,k) is the center and r is the radius of a circle.

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8 0
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Consider the line segment below that is five feet long. Is Q the midpoint of PR? Justify your answer.
givi [52]

Answer:

Q is not the midpoint of PR

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If Q is the midpoint of PR

then

PQ=QR

substitute the given values and solve for x

15x-2=5x+3\\15x-5x=3+2\\10x=5\\x=0.5

Remember that

PR=5\ ft ----> given problem

PR=PQ+QR\\PR=(15x-2)+(5x+3)

substitute the value of x

PR=(15(0.5)-2)+(5(0.5)+3)

PR=(5.5)+(5.5)

PR=11\ ft

Compare with the given value of PR

5\ ft\neq 11\ ft

therefore

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krok68 [10]

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Step-by-step explanation:

5 0
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Write the equation of the line that passes through the points (1, 4) and (9,-8). Put
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Start with the slope formula, shown below.

m = y₂ - y₁ / x₂ - x₁

We take the second y minus the first y over the second x minus the first x.

So we have m = -8 - 4 / 9 - 1 or -12/8.

Notice that -12/8 can be reduced to -3/2.

So the slope of this line is -3/2.

The variable that's used to represent slope is <em>m</em>.

So here, we would say that m = -3/2.

5 0
3 years ago
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