12 yd 4 yd 7 yd 7yd 4yd 4 yd 4 yd 4 yd what is the area

Bella plans to put $200 into a savings account. She can place her money into an account represented by p(x) = 3x + 200, or into

eimsori [14]

P(x) has the highest value in n(x) has the highest value in 15 years

4 0

3 years ago

What percent was the server's tip if the customer left $1.75 for a $12.50 meal.

tatuchka [14]

12.5x=1.75

Solve for x:
1.75/12.5 = 0.14

1. Use the equation 12.5x=1.75
2. Now solve for x.
a. Divide 1.75/12.5
b. Now, you have .14
c. .14 is 14%
3. The answer is 14%

7 0

3 years ago

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

3 years ago

What is m Any answers?

Likurg_2 [28]

Answer:

B. 68°

Step-by-step explanation:

Since, opposite sides of the quadrilateral MNPQ are parallel.

Therefore, it is a parallelogram.

Measures of the opposite angles of a parallelogram are equal.

So,

(6x - 2)° = (4x + 36)°

6x - 2 = 4x + 36

6x - 4x = 36 + 2

2x = 38

x = 38/2

x = 19

$m\angle M = (6x - 2)\degree \\ \\ m\angle M = (6 \times 19- 2)\degree \\ \\ m\angle M = (114- 2)\degree \\ \\ m\angle M =112\degree \\ \\ \because m\angle M + m\angle N = 180\degree \\ (adjacent \: angles) \\ \\ \therefore m\angle N = 180\degree - m\angle M \\ \\ \therefore m\angle N = 180\degree - 112 \degree \\ \\ \therefore m \angle N = 68\degree$

8 0

3 years ago

Is it possible to have a triangle with 150 20 20 degrees angle and why ?

OLga [1]

No, it is not possible. The total measure of all angles in a triangle must be 180. If you add these three together, you get 190.

4 0

3 years ago