Question

ALGEBRA TWO HELP!!!!!!!!!!!!

Answer 1

Answer:

$\frac{p^{-4}q^{5}r^{6}}{p^{-3}qr^{-2}}=p^{-1}q^{4}r^{8}$

Step-by-step explanation:

In division of powers with the same base, we must subtract the exponent of the denominator from the exponent of the numerator:

$\frac{a^{m}}{a^{n}}=a^{m-n}$

Then applying this to the problem:

$\frac{p^{-4}q^{5}r^{6}}{p^{-3}qr^{-2}}=p^{-4-(-3)}q^{5-1}r^{6-(-2)}$

Eliminating the parentheses:

$\frac{p^{-4}q^{5}r^{6}}{p^{-3}qr^{-2}}=p^{-4+3}q^{5-1}r^{6+2}\\ \frac{p^{-4}q^{5}r^{6}}{p^{-3}qr^{-2}}=p^{-1}q^{4}r^{8}$

Answer 2

Answer:   p⁻¹ q⁴ r⁸

Step-by-step explanation:

Use the quotient rule: $\dfrac{x^a}{x^b}=x^{a-b}$

$\dfrac{p^{-4}q^5r^6}{p^{-3}qr^{-2}}=p^{-4-(-3)}q^{5-(1)}r^{6-(-2)}\\\\.\qquad \qquad =p^{-4+3}q^{5-1}r^{6+2}\\\\.\qquad \qquad =p^{-1}q^{4}r^{8}$