Ask question

Ask question

All categories

3 years ago

14

Simon draws a rectangle with 2 two sides that are 2 inches long and two sides that are 3 inches long. Chaz draws a figure with t

he same measurements, but it is not a rectangle. What figure could it be?

1 answer:

dsp733 years ago

7 0

This figure could be a kite.

You might be interested in

If $7500 is invested at an interest rate of 5% each year, what is the value of the investment in 4 years? Write an exponential f

Vanyuwa [196]

The answer is 9,116.3
7500*(1+0.05)^4

3 0

3 years ago

Graph the solution for the following system of inequalities. Click on the graph until the correct solution is displayed. x + y &

Y_Kistochka [10]

Answer:

This is an equation. Solutions: x=1.

5 0

3 years ago

Read 2 more answers

Determine if each of the following sets is a subspace of Pn, for an appropriate value of n.

snow_tiger [21]

Answer:

1) W₁ is a subspace of Pₙ (R)

2) W₂ is not a subspace of Pₙ (R)

4) W₃ is a subspace of Pₙ (R)

Step-by-step explanation:

Given that;

1.Let W₁ be the set of all polynomials of the form p(t) = at², where a is in R

2.Let W₂ be the set of all polynomials of the form p(t) = t² + a, where a is in R

3.Let W₃ be the set of all polynomials of the form p(t) = at² + at, where a is in R

so

1)

let W₁ = { at² ║ a∈ R }

let ∝ = a₁t² and β = a₂t² ∈W₁

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t²) + c₂(a₂t²)

= c₁a₁t² + c²a₂t²

= (c₁a₁ + c²a₂)t² ∈ W₁

Therefore c₁∝ + c₂β ∈ W₁ for all ∝, β ∈ W₁ and scalars c₁, c₂

Thus, W₁ is a subspace of Pₙ (R)

2)

let W₂ = { t² + a ║ a∈ R }

the zero polynomial 0t² + 0 ∉ W₂

because the coefficient of t² is 0 but not 1

Thus W₂ is not a subspace of Pₙ (R)

3)

let W₃ = { at² + a ║ a∈ R }

let ∝ = a₁t² +a₁t and β = a₂t² + a₂t ∈ W₃

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t² +a₁t) + c₂(a₂t² + a₂t)

= c₁a₁t² +c₁a₁t + c₂a₂t² + c₂a₂t

= (c₁a₁ +c₂a₂)t² + (c₁a₁t + c₂a₂)t ∈ W₃

Therefore c₁∝ + c₂β ∈ W₃ for all ∝, β ∈ W₃ and scalars c₁, c₂

Thus, W₃ is a subspace of Pₙ (R)

8 0

3 years ago

The diagram shows a prism.

telo118 [61]

Answer:

Total surface area of the prism = 920 cm²

Step-by-step explanation:

Given prism has 2 similar triangular surfaces and 3 rectangular surfaces of different dimensions.

Area of one triangular side = $\frac{1}{2}(\text{Base})(\text{Height})$

Area of 2 similar sides = Base × Height

= 8 × 15

= 120 cm²

Area of rectangular side with dimensions 17cm × 20cm

Area of the side = 17 × 20 = 340 cm²

Area of the second rectangular side with dimensions 8cm × 20cm

Area of the side = 8 × 20 = 160 cm²

Area of third rectangular side with dimensions 20cm × 15cm

Area of the side = 20 × 15 = 300 cm²

Total surface area of the given triangular prism = 120 + 340 + 160 + 300

= 920 cm²

6 0

3 years ago

Tim and Tom are painters. Tim and Tom are painting a crate. Tom paints 10 sq ft per minute. They painted a particular crate in 1

slava [35]

Tom-------------- >10 sq ft per minute

Tim------------------- >3.5*10=35 sq ft per minute

Both painters (10+35)=45 sq ft per minute

let's assume a cubic unit crate----------> V1=1*1*1=1 feet3

<span>the total surface of the cube is S1=6*(1*1)=6 </span>sq ft

if the volume of the cube increases twice

V2=2 feet3 ------------------- > 2=x*x*x------------- >x=2^(1/3)

And the S2=6*(2^(1/3)*<span> 2</span>^(1/3)=9.5244 sq ft

V2/V1=9.5244/6=1.5874

Therefore

If Tim and Tom----------------------- > take 1 day----------- > to paint a crate V1

For the crate V2------------- > take 1.5874 days

assuming an 8-hour work day

0.5874*8=4.70 hr-------------- > 4 h 42 min

The answer is 1 day 4h 42 min

6 0

4 years ago