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Alla [95]
3 years ago
12

I was asked to find the area of a triangle but all I know is that the longest side of the triangle is 13 units, the shortest sid

e is 7 units, the third side is 8 units, and two of the angle measures are 32° and 28°.
How would you solve this problem?

Mathematics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

24.25

Step-by-step explanation:

  1. let's know what kind of triangle we are dealing with
  • The sum of the degrees of angles in a triangle is = 180

so if both angles given sum up to (32 + 28) = 60, then the other angle is (180 - 60) = 120.

2. Let's draw this triangle    ABC

AB = 13

BC = 7

CA = 8

angle c = 120 degrees

angle b = 32 degrees  

angle a = 28 degrees

3. Now, since it's not a right angled triangle

the formula for calculating the area of a non right angled triangle = 1/2absineC

((7*8) sine 120)/2    

sine 120 = 0.866

(56*0.866)/2 = 24.25

P.S. check the attached image to know what the triangle looks like

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Answer:

the median is 8

Step-by-step explanation:

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3 years ago
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Trapezoid EFGH has the following measurements, where EF is a base and h represents the altitude. EF = 7 cm, FG = 9 cm, GH = 24 c
Reika [66]
From the description we can see that Lines EF and GH are the bases.
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3 years ago
Tan^2 70° -sec^2 70°​
kipiarov [429]

Answer:

-1

Step-by-step explanation:

We need to find the value of tan² 70° -sec² 70°​.

We know that,

\sec^2\theta-\tan^2\theta=1 ...(1)

We can write the given expression as :

tan² 70° -sec² 70° = -(-tan² 70° +sec² 70°)

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4 0
3 years ago
Write an equation of the circle with center (2,-3) and radius 8.
Paul [167]

Answer:

(x-2)^2+ (y+3)^2 = 64

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2+ (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

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3 0
3 years ago
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If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
Marrrta [24]

Answer:

a = 3

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Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

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Equation (2)

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c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0
3 years ago
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