Answer:
A: 64 cubic meters
Step-by-step explanation:
Multiply 7m, 2m, and 4m. You get 56
Then for the smaller cube multiply 2, 2, and 2
X^2/9 +7/3
~I believe this is the answer.
Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
x=95
Step-by-step explanation:
First, we can simplify the equation. 10c-760=190. We can +760 on both sides. 10c=950. We can do 950/10=95.
.7777777778 the calculator says, only because it ran out of room :)