<span>Let P be the cost per pound of peanuts.
Let M be the cost per pound of M&M's.
We can set up two equations to solve this question.
(1) 8P + 5M = 55.27
(2) 6P + 4M = 42.70
Let's multiply equation (1) by 3.
Let's multiply equation (2) by 4.
(1) 24P + 15M = 165.81
(2) 24P + 16M = 170.80
Let's subtract equation (1) from equation (2).
M = 4.99
Let's put M = 4.99 in equation (2) to find P.
6P + 4(4.99) = 42.70
6P = 42.70 - 19.96
6P = 22.74
P = 22.74 / 6
P = 3.79
The cost per pound of peanuts is $3.79
The cost per pound of M&M's is $4.99</span>
Answer:
$4,750
Step-by-step explanation:
Given:
Cost of the equipment = $18,000
Freight charges = $500
Installation cost = $2,500
Estimated salvage value = $2,000
Estimated useful life = 4 years
Now,
The total cost involved with equipment = $18,000 + $500 + $2,500
= $21,000
The Annual depreciation using the straight-line method is given as:
= 
on substituting the respective values, we get
Annual depreciation = 
or
Annual depreciation = $4,750
This is not the most effective graphing type. A line graph is more effective because they are commonly used to express a change over time. In addition, line graphs are also used to compare numerical factors that would have an effect on each other. This is true for number of suits and time. Furthermore, bar graphs are commonly used to compare a quantitative (numerical) and qualitative (non-numerical) factor that do not affect each other. For example, store number and number of suits sold would be a bar graph.
Answer: 3
Explanation:
I added a picture please check it out
T in the independent variable because it does not change based on the other variable. The other variable (C) changes based on it.<span />
