The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.
The mass of NaOH is 45 g
The molar mass of NaOH = 40 g/mol
The moles of NaOH = mass / molar mass
= 45 / 40
= 1.125
Thus, 1.125 mol NaOH is available
3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl
3 mol of NaOH react with 1 mol of FeCl₃
1.125 moles of NaOH will react with x moles of FeCl₃
x = 1.125 / 3
x = 0.375 mol
0.375 mol FeCl₃ can take part in reaction
The molar mass of FeCl₃ is 162 g/mol
The mass of FeCl₃ = moles × mass
= 0.375 × 162
= 60.75 g
Thus, the amount of FeCl₃, which can be consumed is 60.75 g
When light firm the sun passes through matter it’s slows down
Answer:
107,200J or 25.62 kcal
Explanation:
The latent heat of water is 4.2J/g °C so the energy needed to increase the tempearture from 80 °C to 100°C will be:
40g * 4.2J/g °C * (100-80°C )= 3,360J
The heat of vaporization of water is 2260J/g so the energy need to change water from liquid to gas is:
40g * 2260J/g = 90,400J
The heat needed to increase steam temperature should be same as latent heat of water, 4.2J/g °C . So, the energy needed to increase temeprature from 100 to 180 will be:
40g * 4.2J/g °C * (180-100°C )= 13,440J
The total energy needed will be: 3,360J + 90,400J +13,440J= 107,200J
Answer:
D. h = ( P - Po ) / ρg
Explanation:
clearing h:
⇒ P - Po = ρgh
⇒ ( P - Po ) / ( ρg ) = h
