Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Blue area = big rectangle area - small rectangle area
= 14 x 14 - 8 x 10
= 196 - 80
= 116 cm2
Edit - sorry didnt see the other person already solved the prob in comments :)
$270 (i think i could be completely wrong though)
Answer:
The new price is $/£1.25
Step-by-step explanation:
the greatest common factor 80 and 96 is 16. And so 16 party bags she can make .
<u>Step-by-step explanation:</u>
Here we have , Candice is making some party bags for her birthday party she has 96 stickers and 80 boxes of cookies she wants each party bags to be the same and she wants to use all of the stickers and cookie . we need to find how many party bags she can make . Let's find out:
Let's calculate GCF of 96 & 80 as :
Prime factors of 96 are :
⇒ 
Prime factors of 80 are :
⇒ 
Therefore , GCF is common factor of Prime factors of 96 and Prime factors of 80 i.e. 
.
We found the factors and prime factorization of 80 and 96. The biggest common factor number is the GCF number. So the greatest common factor 80 and 96 is 16.
