Answer:
d)
because that would be the same as 
Answer:
0.6517
Step-by-step explanation:
Given that in a certain game of chance, your chances of winning are 0.3.
We know that each game is independent of the other and hence probability of winning any game = 0.3 (constant)
Also there are only two outcomes
Let X be the number of games you win when you play 4 times
Then X is binomial with p = 0.3 and n =4
Required probability
= Probability that you win at most once
= 
We have as per binomial theorem
P(X=r) = 
Using the above the required prob
= 0.6517
Answer:
you have to use cross-multiplication in order to find out the answer to this question.
Step-by-step explanation:
9/12 times 2/3
Answer: this is our required factor i.e.

Explanation:
Since we have given that

As we know the identity , which says that

So, we can use this here ,

Hence this is our required factor i.e.

Answer:
I would say the answers would be A and B. This is because they each get a fair chance.