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Alenkinab [10]
3 years ago
15

If the atmospheric pressure at Mangamaunu Beach is 1000 millibars and we assume the general guideline that atmospheric pressure

decreases by approximately 50% for every 5-kilometer increase in altitude, what will the atmospheric pressure be at the summit of Manakau?
Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

Atmospheric Pressure = 739.2 millibars

Step-by-step explanation:

To answer this question one should assume that Mangamaunu Beach is at sea level ( altitude = 0 m) and that the summit of Manakau is at 2608 meters.

The change in atmospheric pressure with altitude in the first 5 km can be roughly represented by a linear relationship with slope "m" as follows

(500-1000) = m(5000 - 0)\\m = -0.10

Giving the following equation:

(Pressure - 1000) = -0.10Height

Applying for Height = 2608 m

Pressure = -0.10(2608) + 1000\\Pressure = 739.2 millibars

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Rudiy27

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520

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PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLEIST​
solmaris [256]

Answer:

50 cm^2

Step-by-step explanation:

area of rectangle = base * height

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2 years ago
From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.
Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

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The distance to the ship A is d_1 and it is given by

tan (61^o)= \dfrac{50}{d_1}

d_1=\dfrac{50}{tan (61^o)}

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And the distance to the ship B is d_2 and is given by

tan (28^o)= \dfrac{50}{d_2}

d_2=\dfrac{50}{tan (28^o)}

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