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3 years ago

List all of the factors of 72

Mathematics

2 answers:

Marrrta [24]3 years ago

6 0

1,2,3,4,6,8,9,12,18,24, 36 and 72

True [87]3 years ago

3 0

Well the factors of "72" is→ 1,2,3,4,6,8,9,12,18,24,36,72

To find the factor(s) "72" just write out the muliples that equals 72

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Solve the following compound inequality <br> 12 < 2x-4/3 < 16 <br> step by step

motikmotik

Answer:

x∈(20/3;26/3)

Step-by-step explanation:

12 < 2x-4/3 < 16

first we add 4/3 to each side

12+4/3<2x<16+4/3

we bring to the same denominator

12*3/3+4/3<2x<16*3/3+4/3

(36+4)/3<2x<(48+4/3)

40/3<2x<52/3

now we divide by 2

20/3<x<26/3

x∈(20/3;26/3)

4 0

3 years ago

What is the vertex of the graph of this equation y=2x^2+8x-24

sdas [7]

Answer:

The vertex would be D) (-2, -32)

Step-by-step explanation:

To find the vertex , start by find the x-value. For this we can use the equation below.

x = -b/2a

In which a is the coefficient of x^2 and b is the coefficient of x.

x = -b/2a

x = -(8)/2(2)

x = -8/4

x = -2

Now that we have x, we find y by plugging -2 in for each x.

y = 2x^2 + 8x - 24

y = 2(-2)^2 + 8(-2) - 24

y = 2(4) - 16 - 24

y = 8 - 16 - 24

y = -32

3 0

3 years ago

valina [46]

I think 28fa haha s an

6 0

3 years ago

What are rexx sample?

Reil [10]

Answer:

Following are the Arithmetic Operators available in Rexx. Operator, Description, Example. +, Addition of two operands, 1 + 2 will give 3

Step-by-step explanation:

7 0

3 years ago

Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f

AlladinOne [14]

Answer:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

$\hat p=0.64$ estimated proportion of interest

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:

Null hypothesis: $p =0.5$

Alternative hypothesis: $p > 0.5$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

7 0

3 years ago