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jeka94
3 years ago
8

The basic formula for the price elasticity of demand coefficient is

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0

Basic formula for the price elasticity of demand coefficient is on this webside:

http://www.economicsdiscussion.net/price-elasticity-of-demand/price-elasticity-of-demand-with-formula/25223

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Hi! im not sure if my answer is correct or not can someone check me :)
Maslowich
It is correct goodluck
7 0
3 years ago
What’s the solution for 6(2m - 3) - 3m= 2m - 18 + m
katen-ka-za [31]

Answer:

12m-18-3m=2m+m-18

9m-18= 3m-18

9m-3m=18-18

6m=0

m=0/6=0

Step-by-step explanation:

5 0
3 years ago
5. Find the coordinates of the midpoint of the segment whose endpoints are 1l(6, 4) and K(2. 8).
Cerrena [4.2K]

Answer:

5. D (4,6)

6. B (7.8)

Step-by-step explanation:

5. Add the two X coordinates (6+2) and divide that by 2 (8/2=4), do the same for the two Y coordinates (4+8=12, 12/2=6)

6. Use the distance formula \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}\\

Input the coordinates \sqrt{(3-8)^{2}+(8-2)^{2}

3 0
3 years ago
Read 2 more answers
Investment banks generally provide all the following services except:
Natasha_Volkova [10]

Answer:

D. making loans to businesses for capital investment.

Step-by-step explanation:

We can define the responsibilities of investment bans like- these banks specialize in complex financial transactions like underwriting.

These also play the role of broker or financial adviser for institutional clients. These banks helps organisations to raise capital.

These also help companies and governments issue new securities.

So, the answer is -

Investment banks generally provide all the following services except: making loans to businesses for capital investment.

7 0
3 years ago
Read 2 more answers
Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of i
Leokris [45]

Answer:

The mean carrying load of the beams tested is 908.7 pounds per square foot

Step-by-step explanation:

1. Data class 1: 860-879

Midpoint 1: M1=(860+879)/2=1,739/2→M1=869.5

Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

Number of values in data class 3: n3=10

4. Data class 4: 920-939

Midpoint 4: M4=(920+939)/2=1,859/2→M4=929.5

Number of values in data class 4: n4=6

5. Data class 5: 940-959

Midpoint 5: M5=(940+959)/2=1,899/2→M5=949.5

Number of values in data class 5: n5=1


Mean=Sum(Mi*ni)/Sum(ni)

Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

3 0
4 years ago
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