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4 years ago

Evaluate x2/y + x2/z for x = 6, y = -4, and z = -2.

Mathematics

2 answers:

8_murik_8 [283]4 years ago

7 0

Answer:

-27

Step-by-step explanation:

6^2=36

36/-4=-9

36/-2=-18

-9+-18=-9-18=-27

tatiyna4 years ago

3 0

Answer:

-27

Step-by-step explanation:

x^2/y + x^2/z

Let x = 6, y = -4, and z = -2

(6^2)/-4 + (6^2)/-2

PEMDAS says exponents firs

36/-4 + 36/-2

-9 + -18

-27

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A deck of cards is shuffled and dealt to four players, with each receiving 13 cards. Find: a. the probability that the first pla

astra-53 [7]

Answer: A.4/52

B.1/52

C.4/42

D.12/52

Step-by-step explanation:

A. Because there is 52 cards in a deck the answer will be out of 52. Since there is 4 aces in the whole deck the probability of player one getting all four aces is a 4/52.

B. Since there is 52 cards in a deck and only one ace of hearts it will be a probability of 1/52.

C. Since there are 52 cards in a deck the probability that they will hold an ace card is a 4/52 Bc there are four aces.

D. Because there are 52 cards in a deck, and 12 hearts in the deck in all they will have a chance of 12/52

You might need to simplify these fractions or convert to a percentage based on what your instructor wants.

8 0

4 years ago

What is 16% of 43 minutes

Genrish500 [490]

6.88 i hope this helps u

8 0

3 years ago

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Type the correct answer in each box,

Sauron [17]

Answer:

The $n^{th}$ sequence aₙ = -15 +5n

The fifth term of the sequence

a₅ = 10

Step-by-step explanation:

Step(i):-

Given sequence

-10,-5,0,5,10,15,20,.....

The first term = -10

The difference of two terms in the given sequence is equal

d = -5-(-10) = -5 + 10 = 5

d = 0 -(-5) = 5

The given sequence is in arithmetic progression

Step(ii):-

The $n^{th}$ sequence

$a_{n} = a+(n-1) d$

aₙ = -10 +(n-1) 5

aₙ = -10 + 5n -5

aₙ = -15 +5n

Step(iii):-

The $n^{th}$ sequence aₙ = -15 +5n

put n = 5

a₅ = -15 + 5(5) = -15 +25 = 10

Final answer:-

The $n^{th}$ sequence aₙ = -15 +5n

The fifth term of the sequence

a₅ = 10

6 0

3 years ago

Here are the endpoints of the segments BC, FG, and JK. B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

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2 years ago

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I think it’s gonna be d.

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3 years ago

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