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Y_Kistochka [10]
3 years ago
5

I am very confused please solve and explain.

Mathematics
2 answers:
e-lub [12.9K]3 years ago
6 0

Answer:

c = \frac{b^2-R^2}{4a}

Step-by-step explanation:

Given

R= \sqrt{b^2-4ac}

Clear the radical by squaring both sides

R² = b² - 4ac ( subtract b² from both sides )

R² - b² = - 4ac ( multiply all terms by - 1 )

b² - R² = 4ac ( divide both sides by 4a )

\frac{b^2-R^2}{4a} = c

Goryan [66]3 years ago
6 0

Answer:

c=\frac{b^2-R^2}{4a}

Step-by-step explanation:

First, get rid of the square root by squaring both sides:R^{2}=b^{2}-4ac

Next, add 4ac to both sides: 4ac+R^{2}=b^{2}

Then, subtract R^{2} from both sides: 4ac=b^{2}-R^{2}

Finally, divide both sides by 4a to get your answer: c=\frac{b^2-R^2}{4a}

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Audrey's bank account is currently at $75 a fee of 12.50 is deducted each month from Audreys she must maintain a balance greater
meriva

Answer:

5 months

Step-by-step explanation:

Current balance = $75

Monthly deductions = $12.50

75 - 12.5h

Where ,

h = number of months for deduction

she must maintain a balance greater than zero dollars

how many months will Audrey's account stay above zero dollars

0 > 75 - 12.5h

0 - 75 > -12.5h

-75 > - 12.5h

h < -75 / 12.5h

h < 6 months

h < 6 months means h must be less than 6 months which is 5 months

Audrey's account will stay above zero dollars for 5 months and will equal zero dollars in the 6th month

8 0
3 years ago
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omeli [17]
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3 years ago
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tino4ka555 [31]

Answer:

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6 0
3 years ago
4(9-x)6-6(4-7x)&gt;5(1-2x)-8x+9(6-x)
Kazeer [188]

Answer:

x > 133/45

WORKING :

Multiply the number : 4 . 6 = 24

24(9-x) - 6 (4 - 7x) > 5 (1 - 2x) - 8x + 9 (6-x)

expand 24(9 - x) - 6(4 -7x) : 18x + 192

expand 5(1-2x) - 8x + 9(6-x) : - 27x + 59

18x + 192 > -27x + 59

subtract 192 from both sides

18x + 192 - 192 > -27x + 59 - 192

simplify

18x > -27x - 133

add 27x to both sides

18x + 27x > - 27x - 133 + 27x

simplify

45x > - 133

Divide both sides by 45

45x/45 > 133/45

Simplify

x > 133/45

FINALLY ANSWER :

X > 133/45

6 0
3 years ago
What are the rise and run of the line whose equation is y=15x ?
butalik [34]

y = mx , where m is a slope,

m= rise/run

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