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tino4ka555 [31]
3 years ago
15

On line A, each time x increases by 1 y increases by A) .5 B) 1 C) 1.5 D) 2

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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How much of the circle is shaded 1/9 and 1/2
Sholpan [36]

Answer:

4.5 or 4 1/2 they are both the same

Step-by-step explanation:

simple math

5 0
3 years ago
The triangles are similar.
Elenna [48]

Answer:

x = 12

Step-by-step explanation:

The triangles are similar so we can use ratios

4x+12      32

-------  = ------------

15             8

Using cross products

(4x+12) *8 = 15 * 32

(4x+12) *8 = 480

Divide each side by 8

(4x+12) *8/8 = 480/8

4x+12 = 60

Subtract 12 from each side

4x+12 -12 = 60-12

4x = 48

Divide by 4

4x/4 = 48/4

x = 12

8 0
3 years ago
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Asap plz solve problem give brainliest​
Eduardwww [97]

Answer:

The value of x is 84 and the remaining angles are: 76° and 86°

Step-by-step explanation:

Given three angles are

18

x-8

and

x+2

We have to find the angles and for that we have to find the value of x

As we know that the sum of internal angles of a triangle is 180°

So,

18+(x-8)+(x+2) = 180\\18+x-8+x+2 = 180\\2x+12 = 180\\2x = 180-12\\2x = 168\\x = \frac{168}{2}\\x = 84

And the angles are:

x-8 = 84-8 = 76

x+2 = 84+2 = 86

Hence,

The value of x is 84 and the remaining angles are: 76° and 86°

8 0
3 years ago
Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

1/cos^2x = 1 + sin^2x/cos^2x

<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
3 years ago
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For Khloe's lemonade recipe, 8 lemons are required to make 10 cups of lemonade. How many lemons for 30 cups of lemonade?
Margaret [11]

Answer: 24 lemons

Step-by-step explanation: Good luck! :D

8 lemons - 10 cups

16 lemons - 20 cups

24 lemons - 30 cups

6 0
3 years ago
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