<h3>
Answer: </h3><h3>
speed of train A = 44 mph</h3>
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Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
We know that
scale factor=1 in/7.5 ft
scale factor=measurements on the blueprint/measurements <span> in the actual
</span>measurements on the blueprint=[measurements in the actual*scale factor]
so
for 18 ft
measurements on the blueprint=[18 ft*(1 in/7.5 ft)-----> 2.4 in
for 16 ft
measurements on the blueprint=[16 ft*(1 in/7.5 ft)-----> 2.1 in
the dimensions on the blueprint are
2.4 in x 2.1 in
Answer:
its option C
Step-by-step explanation:
Ten x plus four divided by seven
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>