In the problem it is already given that Weston Laundry washed 285.38 pounds of towel and 353.47 pounds of sheets from local hotels in 1 day. Firstly we have to find the total pounds of linens that Weston Laundry has washed in 7 days. Then only will it be possible to find the amount of linen washed in a day.
Then t
Total linen washed by Weston Laundry in 7 days = (285.38 + 353.47) pounds
= 638.85 pounds.
Then
The amount of linen washed by Weston Laundry in 1 day = 638.85/7
= 91.26 pounds
So Weston Laundry washed about 91.26 pounds of linen each day.
Answer: A file hosting service, cloud storage service, online file storage provider, or cyberlocker is an internet hosting service specifically designed to host user files. It allows users to upload files that could be accessed over the internet after a user name and password or other authentication is provided.
Step-by-step explanation: there u go
Answer:
Step-by-step explanation:
the distance around the figure--we need to find the perimeter
we have rectangle that has the side, 8 and 15
P(r)=2(8)+2(15)=16+30=46
we also have half of the circle with the diameter =8 and r=4
Circumference =2*3.14*r
C=2*3.14*4=25.12
we need just half of the circle 25.12/2=12.56
P figure=46+12.56=58.56
Area= rectangle=l*w=8*15=120
Area(circle)=3.14*r^2=3.14*16=50.24
half circle 50.24/2=25.12
Area figure=120+25.12=145.12
Answer:

Step-by-step explanation:
Given
Points:


Required
Determine the equation of line that is perpendicular to the given points and that pass through 
First, we need to determine the slope, m of FG

Where
--- 
--- 



The question says the line is perpendicular to FG.
Next, we determine the slope (m2) of the perpendicular line using:


The equation of the line is then calculated as:

Where





Multiply through by 2

Add x to both sides


Hence, the line of the equation is 