(3/5)x - 21. ..............
Answer:
<h2>15.5 units</h2>
Step-by-step explanation:
This problem is on the mensuration of flat shapes, this time a square shape.
we know that the area of a square is given as
area= length*length
area= l^2
from the problem the area is given as
area= 240 units^2
substitute area for the area in the equation and then we solve for length we have
240= l^2
squareing both sides we have
√240= l
l= 15.49 units
to the nearest hundreths it is
15.5 units
3 hours . . . 6 minutes . . . 45 seconds
+ 8 hours . . 55 minutes . . . 20 seconds
________________________________
11 hours . . 61 minutes . . . 65 seconds
But 65 seconds = 1 minute . . . 5 seconds
11 hours . . 62 minutes . . . 5 seconds
But 62 minutes = 1 hour . . . 2 minutes
12 hours . . 2 minutes . . . 5 seconds
I think this is regrouping, but with 60s instead of 10s.
Answer:
B(x) = 2x + 3
Step-by-step explanation:
Given:
Amount used = 3 GB (constant term)
Additional amount for each stream = 2 GB (slope)
Total bandwidth used for x streams
B(x) = 2x + 3
Neighborhood A :
first, put the numbers in order...
2,[2,2],4,(4),5,[5,5],5
5 number summary :
minimum = 2
Q1 = 2
Q2 (median) = 4
Q3 = 5
maximum = 5
IQR = Q3 - Q1......5 - 2 = 3...so the IQR = 3
Neighborhood B :
1,[1,2],2,(3),4,[5,5],12
5 number summary :
minimum = 1
Q1 = (1 + 2) / 2 = 3/2 or 1.5
Q2 (median) = 3
Q3 = 5
maximum = 12
IQR = Q3 - Q1....5 - 1.5 = 3.5
are the box plots symmetrical ?
Neighborhood A : the median is 4.....the minimum is 2....so thats 2 spaces from the median...the maximum is 5....so thats 1 space from the median...and being that they are not the same distance from the median, ur box plot is skewed to the left...so this is not symmetrical
Neighborhood B : the median is 3....the minimum is 1....so thats 2 spaces from the median...the maximum is 12....so thats 10 spaces from the median....these are not symmetrical especially since u have an outlier of 12....this is skewed to the right