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3 years ago

If there are no changes in the oxidation state of the reactants or products of a particular reaction, it means that

Physics

2 answers:

Anon25 [30]3 years ago

8 0

Answer:

It is not a redox reaction.

Explanation:

A redox reaction is a type of reaction in which there is a transfer of electrons between species. The species that gains electrons are the oxidant agent since it will be reduced when it takes the electron of the other species, and vice versa, the specie that loses electrons will be the reductant agent since it will be oxidated when it loses its electron.

Hence in a redox reaction will occur an electron transfer with the following change in the oxidation number between the reactants and the products.

Therefore, If there are no changes in the oxidation state of the reactants or products of a particular reaction, it means that the reaction is not a redox reaction.

I hope it helps you!

RideAnS [48]3 years ago

6 0

Answer:

that reaction is not a redox reaction.

Explanation:

REDOX REACTION:

An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, ion changes by gaining or losing an electron. Redox reactions are common and vital to some of the basic functions of life, including photosynthesis, respiration, combustion, and corrosion or rusting. All redox reactions involve changes in the oxidation state of the reactants or products of a particular reaction.

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Furkat [3]

The answer is A because it describes both toy cars

6 0

3 years ago

Radon-222 transforms into polonium-218 and an alpha particle (he-4). what else is created?

ELEN [110]

Hm pretty much that's all for alpha decay... But always after any alpha or beta decay, gamma photons are released because the daughter products end up in an excited state so they have to release energy through gamma decay

6 0

3 years ago

A composite load consists of three loads connected in parallel. One draws 100 W at a PF of 0.92 lagging, another takes 250 W at

fenix001 [56]

Answer:

a) $I_{RMS} = 4.79 A$

b) $PF = 0.908$

Explanation:

Get the reactive powers for each of the loads:

Reactive power = Real Power * tanθ

For load 1

Active power, P₁ = 100 W

Power factor, $cos \theta_{1} = 0.92$

$\theta_{1} = cos^{-1} 0.92\\\theta_{1} = 23.074$

$Q_{1}= P_{1} tan \theta_{1} \\Q_{1}= 100tan 23.074\\Q_{1}= 42.60 W$

For load 2

Active power, P₂ = 250 W

Power factor, $cos \theta_{2} = 0.8$

$\theta_{2} = cos^{-1} 0.8\\\theta_{2} = 36.87$

$Q_{2}= P_{1} tan \theta_{2} \\Q_{2}= 250tan 36.87\\Q_{2}= 187.5 W$

For load 3

Active power, P₃ = 250 W

Power factor, $cos \theta_{3} = 1$

$\theta_{3} = cos^{-1} 1\\\theta_{3} =0$

$Q_{2}= P_{1} tan \theta_{3} \\Q_{3}= 150tan 0\\Q_{3}= 0 W$

Calculate the total reactive power, $Q_{net} = 42.6 + 187.5 + 0$

$Q_{net} = 230.1 W$

Calculate the total active power, $P_{net} = 100 + 250 + 150 = 500 W$

$S_{net} = P_{net} + Q_{net} \\S_{net} = 500 + j230.1$

$P_{net} = IVcos \theta_{net}$

$\theta_{net} = tan^{-1} \frac{230.1}{500} \\\theta_{net} = 24.712$

V = 115 $V_{rms}$

$500 = I_{RMS} * 115 cos 24.712\\I_{RMS} = 500/104.47\\ I_{RMS} = 4.79 A$

b) Power factor of the composite load is $cos\theta_{net}$

$\theta_{net} = 24.712\\PF = cos 24.712\\PF = 0.908$

4 0

3 years ago

Why the life of a tornado chaser would be exciting and dangerous.

Rina8888 [55]

Explanation:

Tornado chasers are meteorologist who study and predict weather pattern. This helps them in forecasting time and location of the storm. Never the less tornado's and hurricane's can be deadly as they are powerful wind and comes with a little warning. Storm chaser are in path of storm placing scientific equipment's and hoping to get some reading and then quickly they have to retreat themselves to safe place as even a small delay could cost them their lives. Thus,we can say that life of a tornado chaser would be exciting and dangerous.

8 0

4 years ago

an object is placed 15.8 cm in front of a thin converging lens with an unknown focal length. if a real image forms behind the le

storchak [24]

<span>On what:

f (is the focal length of the lens) = ?
p (is the distance from the object to the lens) =15.8 cm
p' (is the distance from the image to the spherical lens) = 4.2 cm

</span><span>Using the Gaussian equation, to know where the object is situated (distance from the point).
</span>
$\frac{1}{f} = \frac{1}{p} + \frac{1}{p'}$
$\frac{1}{f} = \frac{1}{15.8} + \frac{1}{4.2}$
$\frac{1}{f} = \frac{2.1}{33.18} + \frac{7.9}{33.18}$
$\frac{1}{f} = \frac{10}{33.18}$
Product of extremes equals product of means:
$10*f = 1*33.18$
$10f = 33.18$
$f = \frac{33.18}{10}$
$\boxed{\boxed{f = 3.318\:cm}}\end{array}}\qquad\quad\checkmark$

6 0

4 years ago