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2 years ago

Help me besties PLEASE ;-;

Physics

1 answer:

Svet_ta [14]2 years ago

6 0

Answer:

Current in resistors = 1.5 amp

Current in resistors = 0.18 amp

P = 93.75 watts

Explanation:

Given:

1. Three 5 ohm resistor(series)

Voltage = 10 volt

2. Three 5 ohm resistor(parallel)

Voltage = 9 volt

3. Three 5 ohm resistor(series)

Voltage = 6 volt

Find:

Current in resistors

Total power of circuit

Computation:

1. Total resistor (Series) R = R1 + R2 + R3

Total resistor (Series) R = 5 + 5 + 5

Total resistor (Series) R = 15 ohm

I = V/R

Current in resistors = (15)/(10)

Current in resistors = 1.5 amp

2. Total resistor (Series) R = 1/[1/R1 + 1/R2 + 1/R3

Total resistor (Series) R = 1[1/5 + 1/5 + 1/5]

Total resistor (Series) R = 1.67 ohm

I = V/R

Current in resistors = (1.67)/(9)

Current in resistors = 0.18 amp

3. Total resistor (Series) R = R1 + R2 + R3

Total resistor (Series) R = 5 + 5 + 5

Total resistor (Series) R = 15 ohm

I = V/R

I = (15)/(6)

I = 2.5 amp

P = I²(R)

P = (2.5)²(15)

P = 93.75 watts

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Nuclear sizes are expressed in a unit named

o-na [289]

Answer:

Answer is A) Fermi

Explanation:

Fermi is the expressive unit for nuclear sizes. Fermi = 10^-15 meter.

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3 years ago

Recall from Chapter 1 that a watt is a unit of en- ergy per unit time, and one watt (W) is equal to one joule per second ( J·s–1

harkovskaia [24]

Answer:

Explanation:

The energy of a photon is given by the equation $E_p=h f$ , where h is the <em>Planck constant</em> and f the frequency of the photon. Thus, N photons of frequency f will give an energy of $E_N=N h f$ .

We also know that frequency and wavelength are related by $f=\frac{c}{\lambda}$ , so we have $E_N=\frac{N h c}{\lambda}$ , where c is the <em>speed of light</em>.

We will want the number of photons, so we can write

$N=\frac{\lambda E_N}{h c}$

We need to know then how much energy do we have to calculate N. The equation of power is $P=E/t$ , so for the power we have and considering 1 second we can calculate the total energy, and then only consider the 4% of it which will produce light, or better said, the N photons, which means it will be $E_N$ .

Putting this paragraph in equations:

$E_N=(\frac{4}{100})E=0.04Pt=(0.04)(100W)(1s)=4J$ .

And then we can substitute everything in our equation for number of photons, in S.I. and getting the values of constants from tables:

$N=\frac{\lambda E_N}{h c}=\frac{(520 \times10^{-9}m) (4J)}{(6.626\times10^{-34}Js) (299792458m/s)}=1.047 \times10^{19}$

3 0

3 years ago

An electric dipole is formed from ±1.00nC charges spaced 3.00 mm apart. The dipole is at the origin, oriented along the x-axis.

Ronch [10]

Answer:

Value of electric field along the axis and equitorial axis $E=31.25\ N/c$ and $E = 15.625\ N/c$ respectively.

Explanation:

Given :

Distance between charges , $d = 3 \ mm =\dfrac{3}{1000}\ m=3\times 10^{-3}\ m.$

Magnitude of charges , $q=1\ nC = 10^{-9}\ C.$

Dipole moment , $p=qL=10^{-9}\times 3\times 10^{-3}=3\times 10^{-12} \ C\ m.$

Case A) (x,y) = (12.0 cm, 0 cm) :

Electric field of dipole in its axis ,

$E=\dfrac{2kp}{r^3}$

Putting all values and $r=12\times 10^{-2}\ m.$

We get , $E=31.25\ N/c.$

Case B) (x,y) = (0 cm, 12.0 cm) :

Electric field of dipole on equitorial axis ,

$E = \dfrac{kp}{r^3}$

Putting all values and $r=12\times 10^{-2}\ m.$

We get , $E = 15.625\ N/c.$

Hence , this is the required solution.

7 0

3 years ago

The human eye is sensitive to yellow-green light having a frequency of about 5.5x 10^14 Hz (a wavelength of about 550 nm) what i

SVEN [57.7K]

Answer:The human eye is sensitive to yellow-green light having a frequency of about 5.5*10^{14} ... What is the energy in joules of the photons associated with this light? ... As the wavelength and frequency of a wave are related, we can find the energy ... In order to find this value, we need Planck's Constant, h=6.626×10−34 J⋅s h ...

Explanation:

5 0

3 years ago

What happens to the electric potential energy of a negatively charged ion as it moves through the water from the negative probe

Nataly [62]

Answer:

Decreases.

Explanation:

Electric potential energy is the potential energy which is associated with the configuration of points charge in a system and it is the result of conservative coulomb force.

When the negatively charge ion is at the position of the negative probe than its potential energy is positive when it is move towards the positive probe it's potential energy becomes negative due to the negative ion.

Therefore, potential energy is decreases when negative charge ion moves through the water from negative probe to positive probe.

5 0

3 years ago

Help me besties PLEASE ;-;​

Help me besties PLEASE ;-;