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Whitepunk [10]
3 years ago
15

An automobile owner notices that when her car is outfitted with a muffler, the sound from the exhaust pipe is much quieter than

without the muffler. When she asks her automobile technician about how a muffler works, he explains that a muffler is a device that matches the sound coming down the exhaust pipe but with waves out of phase from the pipe. What phenomenon is the automobile noticing and the technician describing?
Physics
2 answers:
satela [25.4K]3 years ago
8 0

Answer:

descrutive ineference

Explanation:

Did it on USA Test Prep

Lisa [10]3 years ago
4 0

Answer: Destructive interference

Explanation:

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A flashlight bulb is connected to a dry cell of voltage 2.25 V. It draws 35.0 mA (1000 mA = 1 A). What is its resistance?
Anarel [89]

The answer & explanation for this question is given in the attachment below.

6 0
3 years ago
A long, thin rod parallel to the y-axis is located at x = -1.0 cm and carries a uniform linear charge density of +1.0 nC/m. A se
Bad White [126]

Answer:

Hhere is the other part of the question ; What is the net electric field due to these rods at the origin? (epsilon not = 8.85*10^-12)

net electric field = 3600N/C

Explanation:

The detailed calculation is as shwon below

8 0
2 years ago
A particle has charge -1.95 nC. (a) Find the magnitude and direction of the electric field due to this particle at a point 0.225
11Alexandr11 [23.1K]

Answer:

a)

346.67 N/C, downward

b)

1.3 m

Explanation:

(a)

q = magnitude of charge on the particle = 1.95 x 10⁻⁹ C

r = distance of location from the charged particle = 0.225 m

E = magnitude of electric field at the location

Magnitude of electric field at the location is given as

E = \frac{kq}{r^{2}}

Inserting the values

E = \frac{(9\times 10^{9})(1.95 \times 10^{-9})}{(0.225)^{2}}

E = 346.67 N/C

a negative charge produce electric field towards itself.

Direction :  downward

(b)

E = magnitude of electric field at the location = 10.5 N/C

r = distance of location from the charged particle = ?

q = magnitude of charge on the particle = 1.95 x 10⁻⁹ C

Magnitude of electric field at the location is given as

E = \frac{kq}{r^{2}}

Inserting the values

10.5 = \frac{(9\times 10^{9})(1.95 \times 10^{-9})}{r^{2}}

r = 1.3 m

5 0
3 years ago
A microwave oven has 1200 W. If it receives 120 V of potential difference, what is the current in the microwave?
8_murik_8 [283]

Answer:

10amps

Explanation:

Given data

Power =1200W

Voltage =120V

Required

The current I

From

P=IV

I= P/V

Substitute

I=1200/120

I= 10amps

Hence the current is 10amps

7 0
2 years ago
A 150 kg safe on frictionless casters is being raised at 1.20m to the bed of a truck using planks 4m long. The force needed to p
Vesnalui [34]
The only thing you need to know in order to solve this task is that <span>plank length (which is force x), should equal the increase in potential energy, so what we have now : (mass)* g * (height).
It has to look like that:  </span>
<span>F * 3.0 = 150 x 9.81 x 1.20 
Then solve for F, the result should be in newtones = 588N

Do hope it makes sense.</span>
3 0
3 years ago
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