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Cerrena [4.2K]
3 years ago
5

<BRound your answer to the nearest hundredth.2А3?B​

Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

∠ B ≈ 41.81°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin B = \frac{opposite}{hypotenuse} = \frac{AC}{AB} = \frac{2}{3} , thus

B = sin^{-1}(\frac{2}{3} ) ≈ 41.81° ( to the nearest hundredth )

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Make d the subject of the formula h = d/3 + 2​
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First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.

d=6/h
4 0
3 years ago
It takes a while for new factory workers to master a complex assembly process. During the first month that the new
Citrus2011 [14]

Answer:

Will I think it will be A

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because it say it was a positive

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2 years ago
Question 2.
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3 years ago
Two angles in a triangle have measures of 25° and 55°.
rosijanka [135]

Answer:

B) 100

Step-by-step explanation:

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4 0
3 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
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