The first set:
3x + 2y = 2 ---1)
5x + 4y = 6 ---2)
From 1), multiply all by 2, 6x + 4y = 4 ---3)
3) - 2),
6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2
Sub in x = 2 into 1),
3(2) + 2y = 2
2y = -4
y = -2
(2 , -2)
The second set:
3x + 2y = 2 ---1)
11x + 8y = 10 ---2)
From 1), multiply all by 4, 12x + 8y = 8 ---3)
3) - 2),
12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
x = -2
From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.
Hope this helped! Ask me if there's any working from here that you don't understand! :)
Answer:−93 3−153−53
Step-by-step explanation:
wrong answer but the answer is on google
Answer:
-1 = 4
0 = -2
1 = -8
5 = -32
Step-by-step explanation:
trust
Answer:
(3m2n4)^3
Step-by-step explanation:
This deals with raising to a power.
(3m2 • (n4))3
m2 raised to the 3 rd power = m( 2 * 3 ) = m6
n4 raised to the 3 rd power = n( 4 * 3 ) = n12
Answer:
it should be 47
Step-by-step explanation:
