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2 years ago

Whats the answer to this?

Mathematics

2 answers:

Yuliya22 [10]2 years ago

8 0

The answer is 63k + 56m

hjlf2 years ago

6 0

Answer:

The answer is 63k +56m

Step-by-step explanation:

First you have to distibute

7(9k+8m)

63k+56m

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I WILL GIVE BRAINLIEST!

Katyanochek1 [597]

Answer:

ANSWERS BELOW

Step-by-step explanation:

she decided to organise a 5k run ( main subject and action )

To raise money for thr families of patients at a local children's hospital ( why the subject took the action )

Drawing on her love of running ( where the subject got the idea for thr action from )

HOPE THIS HELPED

7 0

2 years ago

Help please 15 points up for grabs

Usimov [2.4K]

a) P(3) = $\frac{11}{100}$ (or 0.11 or 11%)

b) Number of sixes = P(6) x 500

= $\frac{12}{100}$ x 500

= 12 x 5

= 60

5 0

2 years ago

According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students report academic consequences o

astraxan [27]

Answer:

The required confidence interval is (3.068,4.732)

Step-by-step explanation:

Consider the provided information.

He plans to use a 90% confidence interval. He surveys a random sample of 50 students. The sample mean is 3.90 alcoholic drinks per week. The sample standard deviation is 3.51 drinks and wants to construct 90% confidence interval.

Thus, n=50, $\bar x$ =3.90 σ=3.51

Now find degree of freedom.

$df=n-1\\df=50-1=49$

The confidence level is 90% and df=49

Therefore,

$\frac{\alpha}{2} =\frac{1-0.90}{2}$

$\frac{\alpha}{2} =0.05$

Now by using t distribution table look at 49 df and alpha level on 0.05.

$t_{\frac{\alpha}{2}} = 1.67653$

Calculate SE as shown:

$SE=\frac{\sigma}{\sqrt{50} }$

$SE=\frac{3.51}{\sqrt{50}}=0.4964$

Now multiply 1.67653 with 0.4964

Therefore, the marginal error is: 1.67653 × 0.4964≈ 0.832

Now add and subtract this value in given mean to find the confidence interval.

$\bar x-E$

Hence, the required confidence interval is (3.068,4.732)

4 0

2 years ago

1.) Alexander jumped off a cliff into the ocean in Acapulco while on vacation. His height as a function of time could be modeled

Dmitrij [34]

So hmmm check the graph below

now.. to find the vertex of any quadratic

$\bf \textit{vertex of a parabola}\\ \quad \\

\begin{array}{lccclll}
h(t)=&-16t^2&+16t&+480\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

so... how long did it take? well, it took $\bf -\cfrac{{{ b}}}{2{{ a}}}$

what was the highest point? well, it was $\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}$

when did he hit the water? well, at y = 0
that is $h(t) = -16t^2 + 16t + 480 \implies 0 = -16t^2 + 16t + 480,$

solve for "t"

6 0

2 years ago

Classify the sequence {an) = {10,4,8/5,16/25,...} as arithmetic, geometric, or neither. If there is not enough information to cl

Vanyuwa [196]

The answer is arithmetic

4 0

2 years ago