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3 years ago

If I have line segmants with the measurements 3in, 5 in and 8 in; can I make a triangle?

Mathematics

1 answer:

Dimas [21]3 years ago

6 0

Answer:

Equilateral Triangle

Side a = 1

Side b = 1

Side c = 1

Angle ∠A = 60° = 1.0472 rad = π/3

Angle ∠B = 60° = 1.0472 rad = π/3

Angle ∠C = 60° = 1.0472 rad = π/3

C=60°B=60°A=60°b=1a=1c=1

Area = 0.43301

Perimeter p = 3

Semiperimeter s = 1.5

Height ha = 0.86603

Height hb = 0.86603

Height hc = 0.86603

Median ma = 0.86603

Median mb = 0.86603

Median mc = 0.86603

Inradius r = 0.28868

Circumradius R = 0.57735

Vertex coordinates: A[0, 0] B[1, 0] C[0.5, 0.86603]

Centroid: [0.5, 0.28868]

Inscribed Circle Center: [0.5, 0.28868]

Circumscribed Circle Center: [0.5, 0.28868]

Step-by-step explanation:

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Answer:

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Question 8

Let the equation of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

y = mx + b

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Since, m = $\frac{y_2-y_1}{x_2-x_1}$

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Since, this line passes through (1, 4),

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Therefore, equation of the line will be,

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m = $\frac{10-4}{2-6}$

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By substituting the value of 'm' in the equation,

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Since, this line passes through (2, 10)

10 = $-\frac{3}{2}(2)+b$

b = 10 + 2

b = 12

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$y=-\frac{3}{2}x+12$

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If I have line segmants with the measurements 3in, 5 in and 8 in; can I make a triangle?​

If I have line segmants with the measurements 3in, 5 in and 8 in; can I make a triangle?