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3 years ago

Solve the proportion. 2/17=x/68 A. 8 B. 34 C. 4 D. 578

Mathematics

2 answers:

Valentin [98]3 years ago

8 0

Answer is A bc ur dividing the quotients together

arlik [135]3 years ago

8 0

Answer:

A. 8

Step-by-step explanation:

you have to cross multiply

2/17 = x/68

2 times 68

17 times x

17x = 136

divide by 17

x = 8

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Let f(x)=e^x and G(x)=x+6. What are the domain and range of g(f(x))?

Lena [83]

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.

Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.

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3 years ago

(1 pt) In a study of red/green color blindness, 950 men and 2050 women are randomly selected and tested. Among the men, 89 have

Ivahew [28]

Answer: (0.066,0.116)

Step-by-step explanation:

The confidence interval for proportion is given by :-

$p_1-p_2\pm z_{\alpha/2}\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}$

Given : The proportion of men have red/green color blindness = $p_1=\dfrac{89}{950}\approx0.094$

The proportion of women have red/green color blindness = $p_2=\dfrac{6}{2050}\approx0.003$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

Now, the 99% confidence interval for the difference between the color blindness rates of men and women will be:-

$(0.094-0.003)\pm (2.576)\sqrt{\dfrac{0.094(1-0.094)}{950}+\dfrac{0.003(1-0.003)}{2050}}\approx0.091\pm 0.025\\\\=(0.09-0.025,0.09+0.025)=(0.066,\ 0.116)$

Hence, the 99% confidence interval for the difference between the color blindness rates of men and women= (0.066,0.116)

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