The Olympics Games that follow the 28th games will be "XXIX Games."
The Olympic Games that follow the 28th Olympic games is the 29th Olympic Games.
29 in Roman numerals is:
= XXVIII
An X in Roman numerals is 10 so the first two Xs are to signify "20."
An "IX" in Roman numerals is "9" which will then take the number to 29.
It will therefore be the "XXIX Olympic Games."
In conclusion, the number 29 is XXIX in Roman numerals so Olympic Games after the 28th games will be "XXIX Games."
<em>Find out more at brainly.com/question/11381536.</em>
Answer:

Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_a%5Eb%5BR%28x%29%5E2-r%28x%29%5E2%5Ddx)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have

and by replacing in the integral we have
![V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_%7Bx1%7D%5E%7Bx2%7D%5B%28lnx%2B5%29%5E2-%28%5Cfrac%7B1%7D%7B2%7Dx%2B3%29%5E2%5Ddx%5C%5C)
and by evaluating in the limits we have

Hope this helps
regards
In this question it basically wants you to leave Y alone in a side of the equation.
In this case,
For 3y=c

For Ay=w

For Y/c=w
Y=cw
For y/a=2c
y=2ac
For a=y+p
y=a-p
For C=y-k
y=C+k
Answer:
f(x + h) = 3x³ + x² + 9h²x + 3h³ + h² + 9hx² + 2hx
General Formulas and Concepts:
- Order of Operations: BPEMDAS
- Distributive Property
- Expand by FOIL (First Outside Inside Last)
- Combining like terms
Step-by-step explanation:
<u>Step 1: Define function</u>
f(x) = x² + 3x³
f(x + h) is x = x + h
<u>Step 2: Simplify</u>
- Substitute: f(x + h) = (x + h)² + 3(x + h)³
- Expand by FOILing: f(x + h) = (x² + 2hx + h²) + 3(x + h)³
- Rewrite: f(x + h) = (x² + 2hx + h²) + 3(x + h)²(x + h)
- Expand by FOILing: f(x + h) = (x²+2hx+h²) + 3(x² + 2hx + h²)(x+h)
- Distribute/Expand: f(x + h) = (x²+2hx+h²) + 3(x³+3hx²+3h²x+h³)
- Distribute 3: f(x + h) = (x²+2hx+h²)+(3x³+9hx²+9h²x+3h³)
- Combine like terms: f(x + h) = 3x³+x²+9h²x+3h³+h²+9hx²+2hx