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Makovka662 [10]
3 years ago
12

What is an equation of the line that passes through the point (-7,-8) and is

Mathematics
2 answers:
myrzilka [38]3 years ago
5 0

Answer:

all work is shown and pictured

Marta_Voda [28]3 years ago
4 0

Answer:

y = 2x - 1

Step-by-step explanation:

The line passes through point (-7,-8)

The line is parallel to line whose equation is 2x - y = 6

Converting the equation of the second line into form y = mx + c;

2x - y = 6 is equal to y = 2x - 6 (the slope of this line is 2)

For parallel lines the value of their slopes is the same.

So our first line passes through point (-7,-8) and has a slope of 2

Taking another point (x,y) on the line;

Slope = Change in y ÷ change in x = \frac{y - - 8}{x - -7} = 2

y + 8 = 2x + 7

y = 2x + 7 - 8

y = 2x - 1

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Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
Jane cycled 32km, correct to the nearest km.
o-na [289]

Answer:

31.5

and

32,4

Step-by-step explanation:

4 0
3 years ago
Adolfo spends $48 on school supplies.The sales tax is 7%.What is the total cost of the supplies?
Ganezh [65]
The answer would be     $51.36

48.00 x 7% = 3.36

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7 0
3 years ago
Help plssss idk what to do!!!!!!!!!
Firdavs [7]

9514 1404 393

Answer:

  y = 1

Step-by-step explanation:

Recognize that 25 and 125 are powers of 5 and rewrite the equation in terms of powers of 5.

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)/(a^c) = a^(b-c)

  (a^b)(a^c) = a^(b+c)

__

Your equation can be written as ...

  25^4\div5^{5y}=125^y\\\\(5^2)^4\div5^{5y}=(5^3)^y\\\\5^{8-5y}=5^{3y}\\\\8-5y=3y\qquad\text{equate exponents of the same base}

Now this can be solved as an ordinary linear equation.

  8 = 8y . . . . . . add 5y to both sides

  1 = y . . . . . . . divide by 8

The solution is y = 1.

4 0
3 years ago
Which values from this set {−12, −9, −3, 0, 3, 6} satisfy this inequality?
Vesna [10]

The values -3, -9 and -12 satisfy the inequality.

In this question we evaluate each element of the set to determine whether value belongs to the inequation given on statement:

x = 0

-13\cdot 0 + 3 \ge 6

3\ge 6 (FALSE)

x= -3

-13\cdot (-3) +3 \ge 6

42\ge 6 (TRUE)

x = -9

-13\cdot (-9)+3 \ge 6

120\ge 3 (TRUE)

x = -12

-13\cdot (-12) +3 \ge 6

159 \ge 6 (TRUE)

The values -3, -9 and -12 satisfy the inequality.

We kindly invite to see this question on inequalities: brainly.com/question/17675534

7 0
2 years ago
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