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forsale [732]
3 years ago
12

A man has a 10m X 10m square garden. In the center is a 2m X 2m square patch which he cannot use. He divides his usable space in

to four congruent rectangular patches, each of which measures
Mathematics
1 answer:
ra1l [238]3 years ago
8 0

Answer:

4m X 6m

Step-by-step explanation:

This is because if there is a 2m square in the middle, there is 8 m of usable space left along both sides of the garden.

Because the 2m square was in the middle, there is 8/2 = 4m along each width of the 4 small rectangles.

Becuase 4m is the width, there is 10 - 4 = 6m along each rectangle's length.

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How do you solve -3x+d=-9
zhuklara [117]
Step 1: Add 3x to both sides.d−3x+3x=−9+3xd=3x−9 = ANSWER

Can you possibly help me on my recent question?
8 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
Help me asap please !!
pav-90 [236]
I’m not positive but I think all you have to do is minus 62 from 180 which would be 119
4 0
2 years ago
I need help ON THIS PLS
Anit [1.1K]

Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

8 0
2 years ago
Please someone help me I'm stuck on my homework for at least a hour
miss Akunina [59]

Pi is 3.14

1st # is 3.13

2nd # is 3.15

These numbers are irrational because pi=infinity

( I am not exactly sure if this is right so don't blame me if you get this wrong, I just tried to help.....) :T

6 0
3 years ago
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